The number of guests coming to Doug McDougal party can be calculated to be 23 people.
<h3>What number of people are coming?</h3>
Doug invited 138 guests and out of this, only 1/6 will be coming.
The number of people coming is therefore:
= Number invited x Proportion coming
Solving gives:
= 138 x 1/6
= 23 people
Find out more on problems involving proportions at brainly.com/question/14581282.
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<h3><u>Analysis </u><u>of </u><u>graph </u><u>:</u><u>-</u></h3>
We have given one graph which is plot between distance and time. where time is in minutes and distance is in seconds.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- For the first 5 minute ( O to A) , The distance is continously increasing 2m / per minute .
- For the 5 minute that is from 5 minute to 13 minute ( A to B) both marellize and her dog wally moving with the constant speed .
- For next 3 minutes that is from 10 minutes to 13 minutes ( B to C) , The distance is continously decreasing with time .
- For next 3 minutes that is from 13 to 16 minutes ( C to D) , Again they moved with constant speed .
- For next 6 minute that is from 16 to 21 minutes ( D to E) . Again, There distance is increasing with time .
- Again For next 4 minutes that is 21 to 25 minutes , they are moving with constant velocity .
<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>
1) Between O and A
- The marellize and wally when moving between O to A , The distance is constantly increasing with time.
- The graph is Straight line
2) Between A and B
- The marellize and wally when moving between A to B, The distance remains the same with time that is they moving with constant speed.
- The graph is constant or steady
3) Between B to C
- The marellize and wally when moving between B to C, The distance is constantly decreasing with time .
- The graph is straight line but it follows decreasing function .
4) For covering the First 6 km ,
<u>According </u><u>to </u><u>the </u><u>graph</u><u>, </u>
- For covering first 6 km, They took 3 minutes.
5) No, Marellize and wally walk does not from where they have started.
<u>According </u><u>to </u><u>the </u><u>graph </u>
- It is end at 5 m instead of 0m .
Answer:
your answer is 4/13ths. #markasbrainliest
Answer:
e. The probability of observing a sample mean of 5.11 or less, or of 5.29 or more, is 0.018 if the true mean is 5.2.
Step-by-step explanation:
We have a two-tailed one sample t-test.
The null hypothesis claims that the pH is not significantly different from 5.2.
The alternative hypothesis is that the mean pH is significantly different from 5.2.
The sample mean pH is 5.11, with a sample size of n=50.
The P-value of the test is 0.018.
This P-value corresponds to the probability of observing a sample mean of 5.11 or less, given that the population is defined by the null hypothesis (mean=5.2).
As this test is two-tailed, it also includes the probability of the other tail. That is the probability of observing a sample with mean 5.29 or more (0.09 or more from the population mean).
Then, we can say that, if the true mean is 5.2, there is a probability P=0.018 of observing a sample of size n=50 with a sample mean with a difference bigger than 0.09 from the population mean of the null hypothesis (5.11 or less or 5.29 or more).
The right answer is e.