Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
Graph b would be my guess!
Answer:
6
Step-by-step explanation:
Slope: 
<u>Use the slope formula</u>

<u>Note</u>
<u></u>
<u></u>

Multiply 4.8 into (20/3), and multiply 16/9 with (1.2b)

Multiply 9 on both sides
19.2b = 32(9)
19.2b = 288 Divide 19.2 on both sides
b = 15