4x2y+X
4(-1)2(7)+(-1)
-4(14)+(-1)
-56+(-1)
-57
Factor by grouping.
0 = (x^3 +4x^2) +(9x +36) = x^2(x+4) +9(x+4) = (x^2+9)(x+4)
The first factor is the difference of squares (in complex numbers), so the form for factoring that can be used:
a^2 - b^2 = (a -b)(a +b)
Here, a=x, b=3i.
Then the factorization in complex numbers is
0 = (x -3i)(x +3i)(x +4)
Solutions are the values of x that make these factors be zero.
x = -4, -3i, 3i
Answer:
For problem 31: 25 counters in the 5th figure, 81 counters in the 9th figure, and 121 counters in the 11th figure.
Step-by-step explanation:
Since in the examples it shows 1 exponent 2, 2 exponent 2, and 3 exponent 2, that means all the rest will have 2 as an exponent. So the fifth figure would be 5 exponent 2, which is 5 times 5 = 25. The 9th figure would be 9 exponent 2, which is 9 times 9 = 81. The 11th figure would be 11 exponent 2, which is 11 times 11 = 121.
Is that all, or do you need answers for #'s 32, 33, and 34?
I believe it’s A hope you get it right
Answer:
The answer is 84.08
Step-by-step explanation:
1) line up the decimal points
2) add it up like any addition problem
3) Place the decimal point right under the placement of the decimal point of the problem
