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nasty-shy [4]
4 years ago
13

Someone please help me!!!!!

Mathematics
1 answer:
Serggg [28]4 years ago
8 0
(3a-7)^2= (3a)^2 - 2*3a*7 + 7^2= 9a^2- 42a+ 49
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Which of the following is the equation of a line perpendicular to the line y=-10×+1 passing through the point (5,7)
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Y = -10x + 1...slope here is -10. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal of a number, flip the number and change the sign. So our perpendicular line will need a slope of 1/10.

y = mx + b
slope(m) = 1/10
(5,7)....x = 5 and y = 7
now sub and find b, the y int
7 = 1/10(5) + b
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