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ss7ja [257]
3 years ago
10

Jane needs 180 centimeters of green cloth and 240 centimeters of red cloth to make her holiday wreath. If she only had the money

to buy 5/6 of each length that she needed, how many centimeters of cloth did she bring home in all?
Mathematics
1 answer:
Sidana [21]3 years ago
5 0

Answer: She brought home 350 centimeters in total

Step-by-step explanation: The question specifies that Jane only had enough money to buy 5/6 of the materials she needed to make her wreath. For her wreath, she would need 180 centimeters of green cloth. However since she can only afford 5/6 of this, what she would end up with is

Green cloth = 180 x 5/6

Green cloth = (180 x5)/6

Green cloth = 900/6

Green cloth = 150 centimeters

Also she would need 240 centimeters of red cloth and since she can only afford 5/6 of the total, she would end up with

Red cloth = 240 x 5/6

Red cloth = (240 x5)/6

Red cloth = 1200/6

Red cloth = 200 centimeters

If she ended up with 150 centimeters of green cloth and 200 centimeters of red cloth, the total length of cloth she would bring home would be

Total = 150 + 200

Total = 350 centimeters

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Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 A) Both are solutions B) Neither
Dahasolnce [82]

Answer:

D) Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

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Put in x =-1 y =9

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Lets check the second point (-2,6)

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7 0
3 years ago
20. Based on student records, 25% of the students at a large high school have a
Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the  probability that the student has a GPA lower than 3.5 and is not taking any AP  classes is calculated as:

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it means that the students that have a GPA lower than 3.5 and are not taking any AP  classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled  in at least one AP class is 0.12

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P(A∪B) = 0.29

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P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

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