Izzys dog is 10 1/2 years old. Car end dog is 18 months old. How many years older is Izzys dog.

1 answer:

dsp733 years ago

6 0

12 months in a year. So 18 months= 1 year and 6 months. Izzys dog is 10 1/2= 10 years and six months. Then subtract 1 year and 6 months by 10 year and six months and it would be exactly 9 years older.

You might be interested in

Ron wants to buy a video game with a selling price of ?$36?, on sale for? 50% off. The sales tax in his state is 5.5 %. How much

cestrela7 [59]

Answer:

Yes, it costs $18.99.

Step-by-step explanation:

The game is originally $36 and a game 50% off is 36/2 = $18.

The sale price is $18.

The state charges 5.5% tax which means you pay 105.5% of the sale price.

1.055(18) = 18.99

The final total is 18.99 which means Ron's $19 is enough.

7 0

2 years ago

How can you use 4×7 to find 8×7

Natasha_Volkova [10]

If you think about it, 4x7 is half of 8x7 (If you multiply 4, 7, and 2, you get 8x7). So really you can just multiply 4x7 by 2 and you will get 8x7!

7 0

2 years ago

Read 2 more answers

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$