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3 years ago

The length of a rectangle is twice its width. If the area of the rectangle is 5 , find its perimeter

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

4 0

Answer:

9.48

Step-by-step explanation:

The perimeter of a rectangle is the distance around the the shape. It can be found by adding each side of the shape to find a total. In contrast, the area of a shape is the amount inside a shape. It is found using multiplication or A = l*w. Since the width is w and the length is twice its width or 2w, use these expressions in the area formula to find their amount. Then add them together to find the perimeter.

$A = l*w5 = w(2w)\\5 = 2w^2\\2.5 = w^2\\1.58 = w$

The width of the rectangle is w = 1.58. The length is 2w = 2 (1.58) = 3.16.

Add these amounts by P = l + l + w + w to find the perimeter.

P = 3.16 + 3.16 + 1.58 + 1.58 = 9.48

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Find the zero of the function /(x) = 5x-3.

Bad White [126]

Answer:

3/5

Step-by-step explanation:

Set it equal to 0

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Then solve for x

5x=3

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Check

5(3/5) - 3

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3 years ago

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Citrus2011 [14]

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3 years ago

Find the missing side. Round to the nearest tenth. <br>A.7.4<br>B.4.4<br>C.6.4<br>D.5.4

Nutka1998 [239]

Answer:

option D

Step-by-step explanation:

take 39 degree as reference angle

using cos rule

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x = 7*0.77

x = 5.39

x = 5.4

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3 years ago

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Elanso [62]

The series of operations for each case are listed below:

GCF / GCF / GCF
GCF / Grouping
Quadratic trinomial
GCF / Quadratic trinomial
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Sum of cubes
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<h3>How to applying factor properties to simplify algebraic expressions</h3>

In algebra, factor properties are commonly used to solve certain forms of polynomials in a quick and efficient way and whose effectiveness is sustained on all definitions and theorems known in real algebra. In this problem, we should explain and show what factor properties are used in each case:

Case 1

5 · x · y³ + 10 · x² · y Given

5 · (x · y³ + 2 · x² · y) GCF

5 · x · (y³ + 2 · x · y) GCF

5 · x · y · (y² + 2 · x) GCF

Case 2

6 · z · x + 9 · x + 14 · z + 21 Given

3 · x · (z + 3) + 7 · (z + 3) GCF

(3 · x + 7) · (z + 3) Grouping

Case 3

a² + 2 · a - 63 Given

(a + 9) · (a - 7) Quadratic trinomial

Case 4

6 · z² + 5 · z - 4 Given

6 · [z² + (5 / 6) · z - 2 / 3] GCF

6 · (z - 1 / 2) · (z + 4 / 3) Quadratic trinomial

Case 5

81 · m² - 25 Given

(9 · m + 5) · (9 · m - 5) Difference of squares

Case 6

8 · x³ - 27 Given

(2 · x - 3) · (4 · x² + 6 · x + 9) Difference of cubes

4 · (2 · x - 3) · [x² + (3 / 2) · x + 9 / 4] Quadratic trinomial

Case 7

27 · b³ + 64 · z³ Given

(3 · b + 4 · z) · (9 · b² - 12 · b · z + 16 · z²) Sum of cubes

Case 8

2 · w³ - 28 · w² + 80 · w Given

2 · w · (w² - 14 · w + 40) GCF

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Case 9

200 · a⁴ - 18 · b⁶ Given

2 · (100 · a⁴ - 9 · b⁶) GCF

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To learn more on polynomials: brainly.com/question/17822016

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7 0

1 year ago

What is 2xy-3yz+5+2yz-xy

melomori [17]

To simplify this expression, we are going to combine like terms.

First, we can see that we have two terms with the variables $xy$ being multiplied together, $2xy$ and $-xy$ . Together, these add to $xy$ , so our expression is now:

$xy - 3yz + 5 + 2yz$

We also have two terms with $yz$ , $-3yz$ and $2yz$ . Together, these add to $-yz$ , so our expression is now:

$xy - yz + 5$

Our final expression is xy - yz + 5.

6 0

3 years ago