If Kyle starts with $600 and wants to end with (at least) $300 She can withdraw up to $600−$300=$300
If he withdraw 20$/ week the 300 will last for 300/20 = 15 weeks
Answer:
$7.7
Step-by-step explanation:
Hello, I can help you with this
you can solve this by using a simple rule of three.
Step 1
define
if the wholesale price for a shirt is $5.50,it is 100 percent
$5.50⇔100%
the new price(x) is 40% more than the original, it means 140%
x ⇔ 140%
the relation is

Step 2
solve for x(isolate x)

the price of the shirt in the department store is $7.7
Have a nice day.
Answer:
x< -1/4
Step-by-step explanation:
- 3/5 x + 1/5 > 7/20
Subtract 1/5 from each side
- 3/5 x + 1/5-1/5 > 7/20-1/5
-3/5x > 7/20 -1/5
Get a common denominator
-3/5x > 7/20 -1/5*4/4
-3/5x > 7/20 -4/20
-3/5x> 3/20
Multiply by -5/3 to isolate x
Remember that flips the inequality
-5/3* -3/5 x < 3/20*-5/3
x < -1/4
Answer:
Step-by-step explanation:
Hello!
So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:
X: "Lifetime of one shoe pair of the new model"
Applying CLT:
X[bar]≈N(μ;σ²/n)
Known values:
n= 30 shoe pairs
x[bar]: 17 months
S= 5.5 months
Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:
H₀:μ=15
H₁:μ≠15
The significance level for the test is given: α: 0.05
Your critical region will be two-tailed:


So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96
Now you calculate your observed Z-value
Z=<u>x[bar]-μ</u> ⇒ Z=<u> 17-15 </u> = 1.99
σ/√n 5.5/√30
Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.
I hope you have a SUPER day!
Answer:
Well, you could always just put it onto a scale to find the mass. But assuming you aren't talking about a laboratory setting. sorry if its all werid i cant really put it into how it supposed to be
The general formula is:
ρ
=
m
V
where
ρ
is density in
g/mL
if mass
m
is in
g
and volume
V
is in
mL
.
So to get the mass...
m
=
ρ
V
Or to get the volume...
V
=
m
ρ
When you have the volume and not the density, and you want to find mass, you will need to find the density yourself. It's often readily available on the internet.
Just replace "[...]" with the object you want, and if it's not exactly what you need, consider it an estimate.
These days, you should be able to search for the density of any common object.
When you have the density and volume but not the mass, then just make up a mass.
You shouldn't need specific numbers to do a problem. You can always solve a problem in general and get a solution formula. If you need to, just make up some numbers that you know how to use.