All categories

2 years ago

What is the measure of c to the nearest whole degree?

Mathematics

1 answer:

Georgia [21]2 years ago

6 0

By definition,
tanC = (opposite side)/(adjacent side)
= 8.77/2
= 4.385

From the calculator, obtain
m∠C = atan(4.385) = 77.1°

Answer: 77° (nearest whole degree)

You might be interested in

there are 20 students in the group , 15 from them are athletes. it is taken for competition 10 students. find the probability th

Allisa [31]

Answer:

Step-by-step explanation: The question is a bit unclear?

5 0

2 years ago

"Bill’s nominal income in 1990 was $1,009 per month. The CPI had a value of 149 in 1990 and had a value of 192 in 2017. What is

Bas_tet [7]

Answer:

$677.18

Step-by-step explanation:

Data provided in the question:

Bill’s nominal income in 1990 = $1,009 per month

CPI value in the year 1990 = 149

CPI value in the year 2017 = 192

Now,

The Consumer price index ( CPI ) is given as :

CPI = $\frac{\textup{Cost of basket in the current year}}{\textup{Cost of basket in the base year}}\times100$

thus,

for the given case of year 1990

149 = $\frac{\textup{1,009}}{\textup{Real income in the year 1990}}\times100$

Real income in 1990 = $\frac{\textup{1,009}}{\textup{149}}\times100$

Real income in 1990 = $677.18

4 0

2 years ago

99PTS!!!!!!!! What is the approximate area of this backyard pond?

lozanna [386]

I would say A) is your answer.

This is my choice, so I might be wrong.

Glad I could help, and good luck!

8 0

3 years ago

Read 2 more answers

Which type of equation would best model the data shown?

Aloiza [94]

I have to say <span>C. Exponential</span>

4 0

3 years ago

Prove that sin3a-cos3a/sina+cosa=2sin2a-1

Sloan [31]

Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

$sin(3a)=3sin(a)-4sin^3(a)$

$cos(3a)=4cos^3(a)-3cos(a)$

now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

we can replace it

$=2sin(2a)-1$

so,

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

7 0

2 years ago

Read 2 more answers