Let r be the lesser root and r^2 be the greater.......the sum of the roots = -b/a = -[-6] / 1 = 6
So we have that
r^2 + r = 6 → r^2 + r - 6 = 0
Factor
(r + 3) (r - 2) = 0
So r = -3 or r = 2
Then r^2 = 9 or r^2 =4
And the product of the roots = c/a = k/a = k
So....k = (-3)(9) = -27 or k = (2)(4) = 8
Check
x^2 - 6x - 27 = 0 factors as (x + 3)(x - 9) = 0 and the roots are -3 and 9
x^2 - 6x + 8 = 0 factors as (x -2) (x - 4) =0 and the roots are 2 and 4
Answer:
(x+3)(x-2)
Step-by-step explanation:
We can immediately see that there are roots at x = -3, and x = 2.
Because the website gives us that this in the form of (x + _) (x - _), our anwser is (x+3)(x-2)
oops I just saw your comment. Too late i guess...
Answer:
x = 
Step-by-step explanation:
Given
3x + 2 = 6 ( subtract 2 from both sides )
3x = 4 ( divide both sides by 3 )
x =
I have an answer!
ANSWER: [F] 36 Only 1 Answer!!!
No Explanation Provided!!!
