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Alexeev081 [22]
3 years ago
6

Mr smith math class has 45 student 23 are men and the rest are women. what fraction best represents the number of women in the c

lass? 22/45 23/45 22/23 23/22
Mathematics
1 answer:
Natali [406]3 years ago
6 0
22 of them are women.
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Suppose that you can only use the set of small letters characters (a-z) and odd numbers (1, 3, 5, 7, 9) to set a password. What
Flauer [41]

Answer:

31^8

Step-by-step explanation:

To create a password, you need to select 8 characters (not necessarily different) from the set {1,3,5,7,9,a,b,c,...,z}. Now, this set has 31 elements: the 26 lowercase letters from the alphabet and the 5 odd numbers (1,3,5,7,9).

Now, there are 31 ways to choose the first character, it can be any element from our set. The second character can also be chosen in 31 ways, because there are not restrictions (repetitions, specific characters, etc). Similarly, the third, fourth, fifth, sixth, seventh and eighth characters have 31 possibilities each one.

The number of passwords is the number of ways of selecting the 8 characters, then by the multiplication principle the number of passwords is 31×31×31×31×31×31×31×31=31^8.

6 0
3 years ago
Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 A) Both are solutions B) Neither
Dahasolnce [82]

Answer:

D) Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

Lets check the first point (-1,9)

Put in x =-1 y =9

x+y =8

-1+9 = 8

8 =8

This works

x^2 + y = 10

(-1)^2 +9 =10

1+9 = 10

10 = 10

This works

Lets check the second point (-2,6)

Put in x =-2 y =6

x+y =8

-2+6 = 8

4=8

This  does not work

We can stop now.  (-2,6) cannot be a solution

7 0
3 years ago
A woman bought some large frames for $10 each and some small frames for $5 each add a closeout sale if she bought 20 frames for
vampirchik [111]

Answer:

The quantity of large frames is 7

The quantity of small frames is 13

Step-by-step explanation:

Given as :

The price of each large frames = $ 10

The price of each small frames = $ 5

The total number of both frames bought = 20

The price for both the frames = $ 135

Now,

Let the quantity of large frames = L

And The quantity of small frames = S

So , According to question

The total number of both frames bought = 20

Or, The quantity of large frames + the quantity of small frame = 135

Or, L + S = 20         ......A

And $ 10 L + $ 5 S = $ 135                         ................B

Or, $ 10× ( L + S ) = $ 10× 20

Or, $ 10 L + $ 10 S = $ 200

(  $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135

Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65

Or, 0 + 5 S = 65

∴  S = \frac{65}{5}

I.e S = 13

So, The quantity of small frames = S = 13

Put the Value of S in eq A

So , L + S = 20

Or, L = 20 - S

Or, L = 20 - 13

∴   L = 7

So, The quantity of large frames = L = 7

Hence The quantity of large frames is 7

And   The quantity of small frames is 13   Answer

7 0
3 years ago
Please answer the following??????/
valentinak56 [21]

Answer:

I would be 3 8/10

Step-by-step explanation:

hope this helps

8 0
2 years ago
Please answer!!!! please!!!!!!
olga55 [171]

The problem here is:  Too many words.

If you boil the problem down to the bare facts, the question is:

             "$210 is 15% of what number ?"

I'm pretty sure you can take it from there,
but here's the rest of it anyway:

                                                $210  =  15% of (March amount)

                                                $210  =  0.15 x (March amount)

Divide each side by  0.15 :     $1400 = March amount .

Check:
1400 + 210 =  1610
1.15 x 1400 = 1610                                      yay!
5 0
3 years ago
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