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myrzilka [38]
3 years ago
9

What is the coefficient of the second term in the expression?

Mathematics
2 answers:
KiRa [710]3 years ago
6 0
C) -9
This is because the coefficients can be defined as the numbers before the variables. In this case the second variable reading from left to right is b. The coefficient(number I front of the variable) is negative nine which is answer choice C
marissa [1.9K]3 years ago
4 0

Answer:

Step-by-step explanation:

C) -9

This is because the coefficients can be defined as the numbers before the variables. In this case the second variable reading from left to right is b. The coefficient(number I front of the variable) is negative nine which is answer choice C

Read more on Brainly.com - brainly.com/question/14403827#readmore

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A = (-123) + 77 + (-257) + 23 – 43
irga5000 [103]

Answer:

A=-323

Step-by-step explanation:

A = (-123)+77+(-257)+23-43

A = -46+(-257)+23-43

A = -303+23-43

A = -280-43

A = -323

Hope this helps

7 0
3 years ago
How can I create a sine graph that has a period of 2π and an amplitude of 3?
inna [77]

Hello!


The parent function of the graph of sin is y = sin(x).


Amplitude is the maximum displacement on the graph of a function.

Period is the displacement of x at which the graph of a function begins to repeat.

The period can be found by using the formula: P = \frac{2\pi}{B}.


Since the amplitude is 3, the graph of sin is y = 3sin(x).


Given the period 2π, we can substitute this value into the given formula, P = \frac{2\pi}{B}, to find B.


2π = 2π / B (multiply B to both sides)

2π · B = 2π (divide by 2π)

B = 1


Thus, the equation is y = 3sin(x). I'll post the graph as well.

6 0
3 years ago
What is 5,000 in scientific notation?
eimsori [14]
5.0x103

Bolded=exponent
4 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
Read 2 more answers
PLEASE ANSWER FAST AS POSSIBLE I HAVE 40 LESSONS DUE BY 12 PM :(
Sophie [7]
Try B, hope that helps :)
5 0
3 years ago
Read 2 more answers
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