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jolli1 [7]
3 years ago
14

The pendulum swings at an arc of 30 cm and its successive swings reduced to 10% of the previous swings. What is the total distan

ce travelled by the pendulum after 5 swings? This problem is an example of what sequence?
Mathematics
1 answer:
OleMash [197]3 years ago
3 0

Answer:

S_g=  33.333cm

Step-by-step explanation:

From the question we are told that

Arc of 30 cm

10% reduction after each swing

Generally sum of geometric sequence is given by the equation

    S_g=\frac{a(1-r^n)}{1-r}

Mathematically solving for total distance traveled we have

    S_g=\frac{30(1-(0.10^5)}{1-(0.10)}

    S_g=\frac{30}{0.9}

Therefore the total distance traveled  by the pendulum after 5 swings

    S_g=  33.333cm

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Anthony's OT pay will be $118.875 and his overall pay will be $752.875.

Number of hours Anthony has to work in a week = 5 × 8 = 40 hours.

He worked for = 47.50 hours.

Overtime = 47.50 hours - 40 hours = 7.50 hours

Pay per hour = $15.85 / hour

Overtime pay (OT pay) = $15.85 × 7.50 = $118.875

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Therefore, Anthony's OT pay is $118.875 and his overall pay is $752.875.

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Pam and her brother both open savings accounts. Each begin with a balance of zero dollars. For every two dollars that Pam save i
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Answer:

Ratio [Pam to her brother] = 2:5

Step-by-step explanation:

Given:

Pam saves every two dollar

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Ratio [Pam saving and his brothers saving]

Computation:

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I NEED HELP PLEASE !!!Sketch a rectangular prism that has a volume of 36 cubic cm. Label the dimensions of each side on the pris
navik [9.2K]

Answer:

  • Height: 3cm
  • Length: 6cm
  • Width: 2cm

Step-by-step explanation:

To sketch such a Rectangular Prism, all you need to do is to ensure that the product of the dimensions gives 36 cubic cm.

An example is attached:

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  • Length: 6cm
  • Width: 2cm

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3 years ago
How do you simplify 875/1000
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Find\ GCF(875;\ 1000)

875|5\\175|5\\.\ 35|5\\.\ \ 7|7\\.\ \ 1|\\875=\fbox5\times\fbox5\times\fbox5\times7\\\\1000|5\\.\ 200|5\\.\ \ 40|5\\.\ \ \ 8|2\\.\ \ \ 4|2\\.\ \ \ 2|2\\.\ \ \ 1|\\1000=\fbox5\times\fbox5\times\fbox5\times2\times2\times2

GCF(875;\ 1000)=\fbox5\times\fbox5\times\fbox5=125\\\\\frac{875}{1000}=\frac{875:125}{1000:125}=\frac{7}{2\times2\times2}=\boxed{\frac{7}{8}}
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