All categories

3 years ago

Let f(x) = 1/x+2 and g (x) = 1/x-3. Find (f/g) (x). Assume all appropriate restrictions to the domain. help!!!!

Mathematics

1 answer:

DanielleElmas [232]3 years ago

3 0

Answer:(f/g)(x)=(1+2x)/(1-3x) where x<>0

Step-by-step explanation:

f(x)= 1/x+2= (1+2x)/x , x<>0

g(x)=1/x-3=(1-3x)/x , x<>0

=>f(x)/g(x)= (1+2x)/(1-3x) , x<>0

You might be interested in

Determine which of the following expressions can be factored to (x+ 2)(x +2)

inna [77]

(x+2)(x+2)

x^2+2x+2x+4

x^2+4x+4

Answer : C ( x^2+4x+4)

6 0

3 years ago

Read 2 more answers

Use the number line below to find a fraction that is equivalent to 1/2

Yuliya22 [10]

Answer:

4/8

Step-by-step explanation:

There are an infinite number of fractions equal to 1/2, but the number line in the question has 8 spaces, and shows 1 divided into 8 pieces. Therefore, the answer to this question is likely 4/8.

(may I ask why exactly this is put as a college level problem?)

4 0

3 years ago

Read 2 more answers

5x +2 =22<br><br>what is the answer?

elena55 [62]

Answer:

x=4

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

A person suspects a standard number cube is not so standard. Another person rolls this cube 100 times, and it lands on a six 42

Ksju [112]

Answer:

The chance of an average six-sided number cube landing one one number is 1/6, or approximately 16.67%. When rolling a number cube 100 times, the average number of times it lands on any specific number should be fairly close to 16.67.

A 6 being rolled 42 times and 33 times means that it is <em>very likely</em> not to be a standard number cube. Although we cannot know for certain, the chance of this happening is very low.

3 0

3 years ago

Find the distance from P to l.

ki77a [65]

$Equation\ of\ a\ line\ from\ 2\ points (x_1;\ y_1);\ (x_2;\ y_2):\\\\y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\(-4;\ 2)\ and\ (3;-5)\\subtitute:\\\\y-2=\dfrac{-5-2}{3-(-4)}\cdot(x-(-4))\\\\y-2=\dfrac{-7}{7}\cdot(x+4)\\\\y-2=-(x+4)\\\\y-2=-x-4\ \ \ |add\ x\ and\ 4\ to\ both\ sides\\\\x+y+2=0\\-------------------\\$

$Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}$

4 0

3 years ago