Let's try to simplify x^2 + 16. It's a sum of two squares:
x^2 + 16 = 0
x^2 = -16
The problem is, we can't take a square root of a negative. This is where imaginary numbers come in.
Remember that square roots have a plus or minus symbol outside:
±√-16 = ±4i
Our two roots are 4i and -4i. Therefore, the trinomial simplifies to:
(x + 4i)(x - 4i)
If we attempt to divide x + 4 by these two binomials, we will find that 4 and 4i are not like terms. Therefore, we can't simplify this expression.
Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
Answer:
15
Step-by-step explanation:
2/3 simplified into decimal form would be .6666666666 repeating therefore if you divide 10 by 2/3 it can go in a total of 15 times fully
Answer:
<u>12 ( 3z + 5 )</u>
Step-by-step explanation:
