A=BH
Area=Base*Height
The base is 7 in+6 in which equals 13 inches.
Now were set, 13*45.5
Solve to get the answer 591.5
-Seth
Answer:
False 8^0 is not greater than 8^1
Step-by-step explanation:
8^0 = 1
8^1= 8
8>1
MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90
<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120
answer
<CDE = 120°
Answer:
check below
Step-by-step explanation:
1. c = 68-27 = 41
2. t = 7.9+1.5 =9.4
3. a = 21*3 = 63
4. (multiply whole equation by 8) 8r+6=7, r=1/8
5. x = 25.2/4.2 = 6
6. b = 75/15 = 5
7. A. 6C = 99
B. C = 99/6 = $16.50
The solution represents the cost of one ticket.
The closest to the maximum number of cups the punch bowl can hold is 30
<h3>How to determine the number of cups?</h3>
The given parameters are:
1 cup = 15 cubic inches
Diameter of bowl, d = 12 inches
The radius is the half of the diameter.
So, we have:
r = 6
The volume of the bowl is then calculated using:

This gives

Evaluate
V = 452.16
The maximum number of cups is then calculated using:
Cups = 452.16/15
Evaluate
Cups = 30.1444
Approximate
Cups = 30
Hence, the closest to the maximum number of cups the punch bowl can hold is 30
Read more about volumes at:
brainly.com/question/1972490
#SPJ1