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EleoNora [17]
3 years ago
14

Describe how you would find the maximum and minimum values for tangent of the typical angles used on the unit circle. What are t

hese values?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

<span>3down votefavorite1Find minimum and maximum value of function <span>f(x,y)=3x+4y+|x−y|</span> on circle<span>{(x,y):<span>x2</span>+<span>y2</span>=1}</span>I used polar coordinate system. So I have <span>x=cost</span> and <span>y=sint</span> where <span>t∈[0,2π)</span>.Then i exploited definition of absolute function and i got:<span>h(t)=<span>{<span><span>4cost+3sintt∈[0,<span>π4</span>]∪[<span>54</span>π,2π)</span><span>2cost+5sintt∈(<span>π4</span>,<span>54</span>π)</span></span></span></span>Hence i received following critical points (earlier i computed first derivative):<span>cost=±<span>45</span>∨cost=±<span>2<span>√29</span></span></span>Then i computed second derivative and after all i received that in <span>(<span>2<span>√29</span></span>,<span>5<span>√29</span></span>)</span> is maximum equal <span>√29</span> and in <span>(−<span>45</span>,−<span>35</span>)</span> is minimum equal <span>−<span>235</span></span><span>
</span></span>
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y

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(

1

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−

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(

1

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b

−

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=

a

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2

=

a

(

b

1

)

=

a

b

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b

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8

b

=

a

Plug this into the second equation and solve for

b

:

2

=

(

8

b

)

b

2

=

8

b

2

b

2

=

1

4

b

=

±

1

2

Two equations seem to be possible here. Plug both values of

b

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a

. I'll use the second equation for simpler algebra.

If

b

=

1

2

:

2

=

a

(

1

2

)

a

=

4

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y

=

4

(

1

2

)

x

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b

=

−

1

2

:

2

=

a

(

−

1

2

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a

=

−

4

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−

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2

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=

4

(

1

2

)

x

7 0
4 years ago
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