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EleoNora [17]
3 years ago
14

Describe how you would find the maximum and minimum values for tangent of the typical angles used on the unit circle. What are t

hese values?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

<span>3down votefavorite1Find minimum and maximum value of function <span>f(x,y)=3x+4y+|x−y|</span> on circle<span>{(x,y):<span>x2</span>+<span>y2</span>=1}</span>I used polar coordinate system. So I have <span>x=cost</span> and <span>y=sint</span> where <span>t∈[0,2π)</span>.Then i exploited definition of absolute function and i got:<span>h(t)=<span>{<span><span>4cost+3sintt∈[0,<span>π4</span>]∪[<span>54</span>π,2π)</span><span>2cost+5sintt∈(<span>π4</span>,<span>54</span>π)</span></span></span></span>Hence i received following critical points (earlier i computed first derivative):<span>cost=±<span>45</span>∨cost=±<span>2<span>√29</span></span></span>Then i computed second derivative and after all i received that in <span>(<span>2<span>√29</span></span>,<span>5<span>√29</span></span>)</span> is maximum equal <span>√29</span> and in <span>(−<span>45</span>,−<span>35</span>)</span> is minimum equal <span>−<span>235</span></span><span>
</span></span>
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A tire company has plants in Chicago and Detroit. The Chicago plant can make 600 radial and 100 standard tires per day. The Detr
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Answer:

To minimize the cost, the Chicago plant should run 30 days and the Detroit plant should run 20 days.

Step-by-step explanation:

This is a linear programming question, in which there is a function to optimize (minimize cost) and restrictions, all linear functions.

The objective function is Cost:

C=4000H+3000D

C: cost function

H: days of operation for Chicago plant

D: days of operation for Detroit plant

The restrictions are:

- Minimum requirements for radial tires:

600*H+300*D\geq24,000

- Minimum requirements for standard tires:

100*H+100*D\geq5,000

- Days are positive integers

H,D\geq0

We have 3 points in which 2 of the constraints are saturated. In one of this three points is the minimum cost.

We will evaluate them to find the minimum cost:

Point 1: H=0, D=80

C=4,000*H+3,000*D\\\\C=4,000*0+3,000*80=240,000

Point 2: H=50, D=0

C=4,000*H+3,000*D\\\\C=4,000*50+3,000*0=200,000

Point 3: H=30, D=20

C=4,000*H+3,000*D\\\\C=4,000*30+3,000*20=120,000+60,000=180,000

The third point minimizes the cost.

To minimize the cost, the Chicago plant should run 30 days and the Detroit plant should run 20 days.

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Given:

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