Answer:
\left(x+3\right)\left(x-9\right)
Step-by-step explanation:
It would be C. The right one makes it look horrible compared to the other, if someone did not look at the graph.
Answer:
Step-by-step explanation:
<u>The diameter is the hypotenuse of the triangle:</u>
- d = √8²+6² = √100 = 10 cm
<u>Area of the semicircle:</u>
- A = 1/2πr² = 1/2(3.14)(10/2)² = 39.25 cm²
<u>Area of the triangle:</u>
- A = 1/2bh = 1/2(6)(8) = 24 cm²
<u>Shaded area:</u>
Answer:
PQ = 5 units
QR = 8 units
Step-by-step explanation:
Given
P(-3, 3)
Q(2, 3)
R(2, -5)
To determine
The length of the segment PQ
The length of the segment QR
Determining the length of the segment PQ
From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.
so
P(-3, 3), Q(2, 3)
PQ = 2 - (-3)
PQ = 2+3
PQ = 5 units
Therefore, the length of the segment PQ = 5 units
Determining the length of the segment QR
Q(2, 3), R(2, -5)
(x₁, y₁) = (2, 3)
(x₂, y₂) = (2, -5)
The length between the segment QR is:




Apply radical rule: ![\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%2C%5C%3A%5Cquad%20%5Cmathrm%7B%5C%3Aassuming%5C%3A%7Da%5Cge%200)

Therefore, the length between the segment QR is: 8 units
Summary:
PQ = 5 units
QR = 8 units