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devlian [24]
3 years ago
10

Classify each pair of numbered angles as corresponding, alternate interior, alternate exterior, or none of these.

Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

The answer in the attached figures

Step-by-step explanation:

we know that

When two lines are crossed by another line, the angles in matching corners are called <u>Corresponding Angles</u>. If the lines are parallel then the corresponding angles are congruent

see the attached figure N 1  

When two lines are crossed by another line, the pair of angles on the inner side of each of those two lines but on opposite sides of the transversal, are called <u>Alternate Interior Angles</u>. If the lines are parallel then the alternate interior angles are congruent.

see the attached figure N 2  

<u>Vertical Angles</u> are the angles opposite each other when two lines cross  

see the attached figure N 3      

When two lines are crossed by another line, the pair of angles on the outer side of each of those two lines but on opposite sides of the transversal, are called <u>Alternate Exterior Angles</u>. If the lines are parallel then the alternate exterior angles are congruent.

see the attached figure N 4      

When two lines are crossed by another line, the pairs of angles on one side of the transversal but inside the two lines are called <u>Consecutive Interior Angles.</u> If the lines are parallel then the consecutive interior angles are supplementary.

see the attached figure N 5      

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An infinite number of ratios are equivalent to 3:8. How
Inessa05 [86]

Answer:

See below, please!

Step-by-step explanation:

There are infinite number of ratios equivalent to 3:8 because both numbers can be multiplied by a common number or divided by a common number.

For example, 9:24 would still be equivalent to 3:8 because the common number in our case is 3. See what I mean?

Hope this helped!

3 0
3 years ago
What is the slope / rate of change for 2, 5 and -3, 7​
Nady [450]

Answer:

\displaystyle m=\frac{-2}{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS<u> </u>

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Slope Formula: \displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (2, 5)

Point (-3, 7)

<u>Step 2: Identify</u>

x₁ = 2, y₁ = 5

x₂ = -3, y₂ = 7

<u>Step 3: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope<em> m</em>

  1. Substitute in points [Slope Formula]:                                                             \displaystyle m=\frac{7-5}{-3-2}
  2. [Slope] [Fraction] Subtract:                                                                             \displaystyle m=\frac{2}{-5}
  3. [Slope] [Fraction] Rewrite:                                                                              \displaystyle m=\frac{-2}{5}
4 0
3 years ago
-15=-4m+5<br><br>8n+7=31<br><br>-10=10(k-9)
Korolek [52]
-15=-4m+5\ \ \ |both\ sides\ /+4m\\\\4m-15=5\ \ \ \ |both\ sides\ /+15\\\\4m=20\ \ \ \ |both\ sides\ /:4\\\\\underline{\underline{m=5}}

=========================================================

8n+7=31\ \ \ \ |both\ sides\ /-7\\\\8n=24\ \ \ \ |both\ sides\ /:8\\\\\underline{\underline{n=3}}

=========================================================

10(k-9)=-10\ \ \ \ |both\ sides\ /:10\\\\k-9=-1\ \ \ \ |both\ sides\ /+9\\\\\underline{\underline{k=8}}
6 0
3 years ago
Read 2 more answers
Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ
Deffense [45]

Answer:

\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}

Step-by-step explanation:

Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}

\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16

\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i

6 0
3 years ago
Read 2 more answers
Solve for x −9x+5≤17 OR 13x+25≤−1<br><br><br> correct answer gets: 100 points
dimaraw [331]
-9x+5<17 answer x >-4/3 how I do to it
subtract -5 from both side and you get 12. so it be -9x<12
than you divide -9 from both side because you want x by it self you get -4/3 but you have to flip the sign since is negavite and you will be left over with ×>-4/3
6 0
3 years ago
Read 2 more answers
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