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3 years ago

Classify each pair of numbered angles as corresponding, alternate interior, alternate exterior, or none of these.

Mathematics

1 answer:

maksim [4K]3 years ago

8 0

Answer:

The answer in the attached figures

Step-by-step explanation:

we know that

When two lines are crossed by another line, the angles in matching corners are called Corresponding Angles. If the lines are parallel then the corresponding angles are congruent

see the attached figure N 1

When two lines are crossed by another line, the pair of angles on the inner side of each of those two lines but on opposite sides of the transversal, are called Alternate Interior Angles. If the lines are parallel then the alternate interior angles are congruent.

see the attached figure N 2

Vertical Angles are the angles opposite each other when two lines cross

see the attached figure N 3

When two lines are crossed by another line, the pair of angles on the outer side of each of those two lines but on opposite sides of the transversal, are called Alternate Exterior Angles. If the lines are parallel then the alternate exterior angles are congruent.

see the attached figure N 4

When two lines are crossed by another line, the pairs of angles on one side of the transversal but inside the two lines are called Consecutive Interior Angles. If the lines are parallel then the consecutive interior angles are supplementary.

see the attached figure N 5

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Solve the equation. 5=w2.2

Sedaia [141]

Answer:

The answer is about 2.27

Step-by-step explanation:

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3 years ago

The local public transport authority is conducting research into commuter behaviour. A previous census indicated that the mean c

kondor19780726 [428]

Answer:

$H_0:\mu = 45$ and $H_a:\mu < 45$

$T = 34.88$

The null hypothesis is not rejected

Step-by-step explanation:

Given

Random sample of 50 commuter times

Solving (a): The null and alternate hypothesis

From the question, a previous census shows that:

$\mu =45$ and $\sigma= 9.1$

This is the null hypothesis i.e.

$H_0:\mu = 45$

Reading further, a new test was to show whether the average has decreased.

This is the alternate hypothesis, and it is represented as:

$H_a:\mu < 45$

Solving (b) and (c): The test statistic (T).

This is calculated using:

$T = \frac{\mu}{\sigma/\sqrt n}$

In this case:

$n = 50$ $\mu =45$ and $\sigma= 9.1$

So:

$T = \frac{45}{9.1/\sqrt{50}}$

$T = \frac{45}{9.1/7.07}$

$T = \frac{45}{1.29}$

$T = 34.88$

Solving (c): Accept or reject null hypothesis

$\alpha = 0.05$

First calculate the degrees of freedom (df)

$df = n - 1 = 50 - 1$

$d f = 49$

From the t distribution table,

At: $d f = 49$ , $\alpha = 0.05$ and $T = 34.88$

the t score is:

$p = 1.676$

$p > 0.05$

So, the null hypothesis is not rejected

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3 years ago

The point P(-5,-8) is reflected across the x-axis to create point Q.

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Answer:

Answer: D. Q(5, −6) and R(−5, 6)

Step-by-step explanation:

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3 years ago

Given f(x) and g(x) = f(x) + k, use the graph to determine the value of k.

Slav-nsk [51]

Answer:

find out how many units higher g(x) is compared to f(x).

g(x) is 3 units higher than f(x)

Since the graph is 3 units higher, the value of k must be 3.

Step-by-step explanation:

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3 years ago

57 students choose to attend one of three after school activities: football, tennis or running.

skelet666 [1.2K]

The probability that the randomly selected student chose running is; 12/57

<h3>Solving Probability Questions</h3>

Total number of students = 57

Total number of boys = 24

Total number of girls = 33

Number of Girls that chose football = 17

Number of boys that chose football = 14

Number of students that chose Tennis = 14

Now, number of students that chose running will be;

Number of students that chose running = 57 - (31 + 14) = 12

Thus, probability that a randomly selected student chose running = 12/57

Read more about probability selection at; brainly.com/question/251701

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2 years ago