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pav-90 [236]
3 years ago
11

As a promotional offer, a new gym is offering a 30% discount to those who sign up in the first month. Patty and her 2 siblings t

ake advantage of the offer and sign up for a total amount of €210. What were the total savings mode?
Work out the average savings per person
Mathematics
2 answers:
kirill115 [55]3 years ago
8 0

Answer:

a = €90

b = £30

Step-by-step explanation:

They had a discount of 30% means that they paid  70%.

100% (total percentage ) - 30%( discounted for them) = 70% ( meaning they paid for 70% instead of 100%).

To find the total saving made, we need to know the total cost without the promo and substract from the 70% payment made.

70% payment made = €210.

1% = [210/70 = €3].

if 1% = €3, then 100% willl be €300.

100% the gym offers = €300.

Total saving made = total cost the gym offers - the 70% payment made.

€300 - €210 = €90.

If you want to be sure.  30% of €300 = 90.

meaning that they had a discount of €90.

If they paid €210 + €90 = €300.

b) The avearge saving per person?

Remember the question said Patty and 2 siblings, suggest they are 3 people in the picture.

If the 3 saved €90,

averge of one person:

90/3 = €30

Finger [1]3 years ago
5 0

Answer:

Total\ Savings = 63

Average\ Savings = 21

Step-by-step explanation:

Given

Amount = 210

Savings = 30\%

Solving (a) Total Savings Mode

Total\ Savings = Savings * Amount

Total\ Savings = 30\% * 210

Total\ Savings = 63

Solving (b): Savings per person

Since, there are 3 individuals involved;

Average\ Savings = \frac{Total\ Savings}{3}

Average\ Savings = \frac{63}{3}

Average\ Savings = 21

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Finger [1]

Answer:

Lower limit: 113.28

Upper limit: 126.72

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 120, \sigma = 8

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So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8

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X when Z has a pvalue of 0.20. So X when Z = -0.84

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X - 120 = -0.84*8

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Upper limit

X when Z has a pvalue of 0.80. So X when Z = 0.84

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X - 120 = 0.84*8

X = 126.72

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