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3 years ago

PLEASE HELP ME OUT !!! WILL APPRECIATE IT SO MUCH !!

Mathematics

1 answer:

mash [69]3 years ago

4 0

Start with the general formula. The key word is difference. So the general formula is

D(x) = W(x) - R(x) Now substitute in the values for W(x) and R(x)
D(x) = 0.002x^3 - 0.01x^2 - (x^2 - 4x + 13) Be very careful about the sign in front of the brackets.

D(x) = 0.002x^3 - 0.01x^2 - x^2 + 4x - 13 Do you see what that minus sign did? It affected all 3 terms.

D(x) = 0.002x^3 - 1.01x^2 + 4x - 13 <em>Note: -0.01 - 1x^2 = - 1.01 x^2</em>
That gives you a clear cut answer

C<<<<< answer.

That sign is the worst part of the question. Make sure you understand what it did.

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Given that f(x) = x2 – 3x - 10 and g(x) = x – 5, find (f - g)(x) and express

Roman55 [17]

Answer:

$(f-g)(x)= x^2-4x-5$

Step-by-step explanation:

We have the two functions:

$f(x)=x^2-3x-10\text{ and } g(x)=x-5$

And we want to find (f-g)(x).

(f-g)(x) is equivalent to f(x)-g(x).

Therefore:

$\begin{aligned} (f-g)(x)&=f(x)-g(x)\\ &=(x^2-3x-10)-(x-5)\end{aligned}$

Simplify:

$\begin{aligned} &=x^2-3x-10-x+5 \\ &=(x^2)+(-3x-x)+(-10+5) \\ &=x^2-4x-5\end{aligned}$

Therefore:

$(f-g)(x)= x^2-4x-5$

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