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3 years ago

If an object has the radius of 6 inches then what is the circumference of the object

Mathematics

2 answers:

Ivahew [28]3 years ago

7 0

Answer:

37.68

Step-by-step explanation:

the radius is half of the circle, u multiplied by two to get the diameter and then multiply by 3.14 (pi)

s344n2d4d5 [400]3 years ago

3 0

Answer:

12 inches

Step-by-step explanation:

radius is half of the circumference

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You are running a concession stand at a basketball game. You are selling hot dogs and sodas. Each hot dog costs $2.25 and each s

baherus [9]

The equations and the number of hotdogs and sodas sold are: x+ y = 126 and 2.25x + 1.50y = 225.75 ; 49 hot dogs and 77 sodas.

Two equations can be derived from this question:

2.25x + 1.50y = 225.75 equation 1

x + y = 126 equation 2

Where:

x = number of hotdogs sold

y = number of soda sold

In order to determine the value of y, multiply equation 2 by 2.25

2.25x + 2.25y = 283.50 equation 3

Subtract equation 1 from 3

57.75 = 0.75y

y = 77

Substitute for y in equation 2

x + 77 = 126

x = 49

To learn more about simultaneous equations, please check: brainly.com/question/23589883

8 0

3 years ago

Read 2 more answers

Solve the simultaneous equation 2x+4y=1 3x+5y=7b

Lyrx [107]

Step-by-step explanation:

3x+5y=7b equation 1
2x+4y=1

2x=-4y+1

x=(-4y+1)/2
x=(-4y+1)/2 in equation 1

3×(-4y+1)/2+5y=7b

(-12y+3)/2+5y=7b

(-12y+3+10y)/2=7b

(-12y+3)/2=7b

-12y+3=14b

-12y=14b-3

y=3-14b/12
y=3-14b/12 in x=(-4y+1)/2

x=(-4×{3-14b/12}+1)/2

x=(-3+14b)/3+1/2

x=14b/3×1/2

x=7b/3

8 0

2 years ago

Complete the square to re-write the quadratic function in vertex form: y=x2-x+3

Anna [14]

Answer:

Step-by-step explanation:

hello :

note : the vertex form is :

ax²+bx+c = a(x+(b)/(2a))²- delta/4a² and delta = b²- 4ac

in this exercice you have : a =1 b = -1 and c= 3

continu ..........

5 0

2 years ago

A football is kicked vertically upward from a height of 2 feet with an initial speed of 50 feet per second. The formula h=2+50t-

Oksanka [162]

Answer: 38 feet.

Step-by-step explanation:

The equation of motion of a body thrown vertically upwards:

$\displaystyle\\\boxed {h=h_0+v_0t-\frac{gt^2}{2} \ \ \ \ \ (1)}$ ,

$h_0=2 \ feet\ \ \ \ v_0=50\ feet\ per\ second.$

Substitute in formula (1) the value t=2 c:

$h=2+50*2-16*2^2\\h=2+100-16*2*2\\h=102-64\\h=38\ feet.$

5 0

1 year ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago