Answer:
the answers are a and d
Step-by-step explanation:
x+x+x=3x and you can't add a constant (2) to a variable(3x) so it would just be 3x+2
Answer: -1/2
Step-by-step explanation:
Rise= 1
Run= 2
Answer:
6%
Step-by-step explanation:
57 divided by 80 = 0.5875
.5875 rounded to the nearest tenth is 6%
Answer: t = 10
Step-by-step explanation:m
Given that; n₁ = 10, n₂ = 10
ж₁ = 50, ж₂ = 30
Sˣ₁ = 20, Sˣ₂ = 20
Now using TEST STATISTICS
t = (ж₁ - ж₂) / √ ( Sˣ₁/n₁ + Sˣ₂/n₂ )
so we substitute our figures
t = ( 50 - 30 ) / √ ( 20/10 + 20/10 )
t = 20 / √4
t = 10
For the first boat, 6 knots at a bearing of N39, and for the second boat 4 knots at a bearing of S87°W. the distance of boats at the end of 2 hr and the bearing of 1st to 2nd both is mathematically given as
<h3>What is the distance b/w the boats at the end of 2 hr and the bearing of 1st to 2nd boat?</h3>
Generally, the Relative speed is mathematically given as
V=\sqrt{4^2+6^2+2(4)(6)cos(48)}
V=\sqrt{52+48(0.669)}
X=9.17Knots
Hence, distance b/w the boats
V'=9.17Knots*2
V'=18.34
V'=22.93Km
In conclusion, the bearing of 1st to 2nd boa ist
B=39+90+(90-87)
B=132°
Read more about Speed
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