Answer:
The frequency of the simple harmonic motion of a 67.6 kg diver on the board = 2.48 Hz
Explanation:
The frequency in simple harmonic motion is related to spring constant and mass causing the motion through the relation
f = (1/2π) √(k/m)
When mass = 10 kg, f = 6.90 Hz,
6.9 = (1/2π) √(k/10)
(√(k/10) = 6.9×2π = 43.354
k/10 = 43.354² = 1879.57
K = 18795.7 N/m
When a diver of mass 67 kg climbs the diving board, the total mass on the diving board now becomes (10+67.6) = 77.6 kg
Spring constant of the diving board doesn't change,
So, the frequency is then given by
f = (1/2π) √(18795.7/77.6)
f = 2.48 Hz
Answer:
(a) 112.5 V/m
(b) 0.01494 T
Explanation:
velocity, v = 4.5 km/s = 4500 m/s
magnetic field, B = 2.5 x 10^-2 T
mass, m = 6.64 x 10^-26 kg
charge, q = 1.6 x 10^-19 C = 1.6 x 10^-19 C
(a) The force due to the magnetic field is balanced by the force due to the electric field
q E = B q v
E = B v = 2.5 x 10^-2 x 4500 = 112.5 V/m
(b) radius, r = 12.5 cm
B' = 0.01494 T
The speed that the person needs to leave the ground will be 4.32m/s
From the question given,
Height = 95cm
Since the person leave the ground v = 0m/s
acceleration due to gravity g = 9.8m/s²
Using the equation of motion
v² = u² + 2as
a = -g (upward motion)
s = h (distance changes to height)
The equation will become:
0² = u² - 2gh
0² = u² - 2(9.8)(0.95)
u² = 18.62
u = √18.62
u = 4.32
Hence the speed that the person needs to leave the ground will be 4.32m/s
Learn more here: brainly.com/question/20352766
Explanation:
Given that,
The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.
The mass of each orange is 198 g
We know that,
1 kg = 1000 g
10.222 kg = 10.222×1000 g
Let there are n number of oranges. So,
It means she can send 52 oranges and it is maximum quantity.
