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3 years ago

15

A 206.3 kg walrus initially at rest on a horizontal floor requires a 249 N horizontal force to set it in motion. Find the coeffi

cient of static friction between the walrus and the floor. Use 10 m/s2 for g.

1 answer:

garik1379 [7]3 years ago

6 0

Maximum friction force= 249 N
Normal reaction force=206.3*10=2063 N
Maximum friction force=coefficient of friction*normal reaction force
Maximum friction force/normal reaction force=coefficient of friction
Coefficient of friction=249/2063=0.121

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