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NeTakaya
3 years ago
15

A 206.3 kg walrus initially at rest on a horizontal floor requires a 249 N horizontal force to set it in motion. Find the coeffi

cient of static friction between the walrus and the floor. Use 10 m/s2 for g.
Physics
1 answer:
garik1379 [7]3 years ago
6 0
Maximum friction force= 249 N
Normal reaction force=206.3*10=2063 N
Maximum friction force=coefficient of friction*normal reaction force
Maximum friction force/normal reaction force=coefficient of friction
Coefficient of friction=249/2063=0.121

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what was the temperature change in Celsius degree if it is changed from 44 degree fahrenheit to -56 degree fahrenheit​
wel

Answer:

-11.11 degree Celsius

Explanation:

The change was 44 degree fanhereit

To 56 degree fanhereit

Therefore the temperature range can be calculated as follows

56-44

= 12 degree fanhereit to Celsius

= 12-32×5/9

= -20×5/9

= 100/9

= -11.11 degree Celsius

5 0
2 years ago
The average speed during any time interval is equal to the total distance of travel divided by the total time. Let d represent t
Tanya [424]

Answer:

Average speed = 3.63 m/s

Explanation:

The average speed during any time interval is equal to the total distance travelled divided by the total time.

That is,

Average speed = distance/ time

Let d represent the distance between A and B.

Let t1 be the time for which she has the higher speed of 5.15 m/s. Therefore,

5.15 = d/t1.

Make d the subject of formula

d = 5.15t1

Let t2 represent the longer time for the return trip at 2.80 m/s . That is,

2.80 = d/t2.

Then the times are t1 = d/5.15 5 and

t2 = d/2.80.

The average speed vavg is given by the following equation.

avg speed = Total distance/Total time

Avg speed = d + d/t1 + t2

Where

Total distance = 2d

Total time = t1 + t2

Total time = d/5.15 + d/2.80

Total time = (2.8d + 5.15d)/14.42

Total time = 7.95d/14.42

Total time = 0.55d

Substitute total distance and time into the formula above.

Avg speed = 2d / 0.55d

Avg Speed = 3.63 m/s

7 0
3 years ago
Me ajudem, Por favor!!!!!!
zzz [600]

Answer:

a)  a=4\,\frac{m}{s^2}

b)  V(t)=4\,t\,+3

c)  V(1)=7 \,\frac{m}{s} \\

d)  Displacement = 22 m

e)  Average speed = 11 m/s

Explanation:

a)

Notice that the acceleration is the derivative of the velocity function, which in this case, being a straight line is constant everywhere, and which can be calculated as:

slope= \frac{15=3}{3-0} =4\,\frac{m}{s^2}

Therefore,  acceleration is a=4\,\frac{m}{s^2}

b) the functional expression for this line of slope 4 that passes through a y-intercept at (0, 3) is given by:

y=m\,x+b\\V(t)=4\,t\,+3

c) Since we know the general formula for the velocity, now we can estimate it at any value for 't", for example for the requested t = 1 second:

V(t)= 4\,t+3\\V(1)=4\,(1)+3\\V(1)=7 \,\frac{m}{s}

d) The displacement between times t = 1 sec, and t = 3 seconds is given by the area under the velocity curve between these two time values. Since we have a simple trapezoid, we can calculate it directly using geometry and evaluating V(3) (we already know V(1)):

Displacement = \frac{(7+15)\,2}{2} = 22\,\,m

e) Recall that the average of a function between two values is the integral (area under the curve) divided by the length of the interval:

Average velocity = \frac{22}{2} = 11\, \,\frac{m}{s}

3 0
3 years ago
5.
lesantik [10]

Answer:

It is B

it is called a jumper cable because it jumps the power from one car to the other

3 0
3 years ago
A projectile is launched with a horizontal velocity of 20 m/s and an initial vertical velocity of 20 m/s. What is the projectile
cestrela7 [59]

Answer:

Vertical acceleration 9.8 m/s² downward

Horizontal acceleration 0.0 m/s²

assuming no air resistance.

6 0
3 years ago
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