Shortwave radios have a higher frequency than ultraviolet light
Answer:
0.75 seconds
Explanation:
Given information
Inflow=0.6 cfm
Density of air entering= 0.075 lbm/ft3
Bicycle’s inflated volume= 0.040 ft3
density of air in the inflated tire= 0.4 lbm/ft3
Mass of air pumped=density*volume=0.075*0.04=0.003 lbm
This mass of air pumped is same as mass of air in the inflated tire
Volume of inflated tire=mass/density=0.003/0.4=0.0075 ft3
Time=0.0075/0.6= 0.0125 mins
0.0125*60=0.75 seconds
<span>The force would double.</span>
Formula: F=w*d => d=F/w
Since F=500j, w=50N
=>d= 500/50=10m
So, D=10m
Answer:
<em>The gauge pressure at this height is 304.11 kPa</em>
<em></em>
Explanation:
Height of water is 31.0 m
We know that gauge pressure is the pressure by which a given pressure exceeds the atmospheric pressure. Normally, the absolute pressure due to this height of water would have been the atmospheric pressure plus the gauge pressure due to this height of water. In the case, we only consider the gauge pressure due to the height of water, since the atmospheric pressure is considered the datum pressure.
Gauge pressure of water = ρgh
where ρ is the density of water = 1000 kg/m^3
g is the acceleration due to gravity = 9.81 m/s^2
h is the height = 31.0 m
Gauge pressure of the water = 1000 x 9.81 x 31 = 304110 Pa = <em>304.11 kPa</em>