Answer:
6000000 sq yd
Step-by-step explanation:
Data provided in the question:
Length of the fencing = 7000 yd
let the perpendicular sides be 'P'
and the length parallel to the river be 'L'
according to the given question
L = P + 2500 ............(1)
also,
Length to be fenced = 2P + L
thus,
2P + L = 7000 ...........(2)
substituting L from (1), we get
2P + P + 2500 = 7000
or
3P = 7000 - 2500
or
3P = 4500
or
P = 1500 yd
Thus,
L = 1500 + 2500 = 4000 yd
Therefore,
the area of the rectangular land = L × P = 4000 × 1500 = 6000000 sq yd
<h3>
Answer: 10</h3>
Explanation:
Everywhere you see an x, replace it with 5. Then simplify using PEMDAS
f(x) = x^2 - 3x
f(5) = 5^2 - 3(5) ... plug in x = 5
f(5) = 25 - 15
f(5) = 10
Answer:
![\frac{1}{4}^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%5E%7B2%7D)
Step-by-step explanation:
When you solve these two equations, you end up with the same answer of 1/16 or 0.0625
No image shown but just remember that percentage is out of 100
0.03 is 3%