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In-s [12.5K]
3 years ago
13

Which function does the graph represent? f(x) = log(x + 3) + 1 f(x) = log(x + 1) + 3 f(x) = log(x + 1) – 3 f(x) = log(x – 3) + 1

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0

Answer:

f(x) = log(x + 1) + 3

Step-by-step explanation:

plato users

Anettt [7]3 years ago
4 0
It'd be a lot easier to help you if you'd share the answer graphs.

Just so that you know:

<span>f(x) = log(x + 3) + 1 can be graphed as follows:
</span>
1.  Graph y = log x.  This function's domain is x>0.  It begins in Quadrant IV and ends in Quadrant I.  It intercepts the x-axis at (1,0).

2.  Now move the entire graph 1 unit to the left.  This gives you the graph of y = log (x+1).

3.  Now translate this entire graph up 3 units.  This gives you the graph of <span>f(x) = log(x + 3) + 1.</span>
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Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))
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By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ \sqrt[n]{z} =  \sqrt[n]{a} \ (cos \  \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )
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For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>

Part (A) <span>find the modulus for all of the fourth roots
</span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root = \sqrt[4]{z} =  \sqrt[4]{81} = 3

Part (b) find the angle for each of the four roots

The angle of the given complex number = \frac{3 \pi}{8}
There is four roots and the angle between each root = \frac{2 \pi}{4} =  \frac{\pi}{2}
The angle of the first root = \frac{ \frac{3 \pi}{8} }{4} =  \frac{3 \pi}{32}
The angle of the second root = \frac{3\pi}{32} +  \frac{\pi}{2} =  \frac{19\pi}{32}
The angle of the third root = \frac{19\pi}{32} +  \frac{\pi}{2} =  \frac{35\pi}{32}
The angle of the  fourth root = \frac{35\pi}{32} +  \frac{\pi}{2} =  \frac{51\pi}{32}

Part (C): find all of the fourth roots of this

The first root = z_{1} = 3 ( cos \  \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})
The second root = z_{2} = 3 ( cos \  \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})

The third root = z_{3} = 3 ( cos \  \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})
The fourth root = z_{4} = 3 ( cos \  \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})
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