Answer:
26°
Step-by-step explanation:
AC=tan 64
BC=x=sec 64
Using sine rule
(Sin 64)/tan 64 = (sin BAC)/sec 64
Cos 64 = (sin BAC)(cos 64)
Sin BAC= 1
BAC=90
ACB+ 64+90=180
ACB= 26°
The expression should be (2/h)x(k+8).
Answer:
thx
Step-by-step explanation:
Answer:
X = 2
Y = 1
Step-by-step explanation:
x + 4y = 6
3x + 3y = 9
3x + 12y = 18
3x + 3y = 9
9y = 9
x + 4y = 6
y = 1
x + 4 * 1 = 6
y = 1
x + 4 = 6
y = 1
x = 2
so there ia only 1 solution for this equation is (2;1)
Done :))
Answer:
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Step-by-step explanation:
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












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Hope I helped!
Best regards! :D
~