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gregori [183]
3 years ago
11

A car dealer offers 5 different models, 6 colors, and 3 kinds of transmissions. How many unique cars could you choose from at th

is dealership? to this you do 5*6*3 right?
Mathematics
2 answers:
zimovet [89]3 years ago
8 0
The answer is 90 because 5x6x3.
Harlamova29_29 [7]3 years ago
8 0

Answer: 90 A P E X

Step-by-step explanation:

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If a procedure meets all of the conditions of a binomial distribution except the number of trials is not​ fixed, then the geomet
natima [27]

Answer:

Given p = 0.07 as the probability that someone is a universal donor

In case of Geometric Distribution, Probability of  getting the first success on nth trial is given by

P (X=n) = p (1-p) ^ {n-1}

where p is the probability of success on any one trial and (1-p) shows the probability of failure.

So the probability of the first subject to be a universal blood donor will be the seventh person is

P (X=7) = 0.07 (1-0.07) ^ {7-1} = 0.07 (0.93) ^ 6 = 0.07*0.647 = 0.0453

So the final probability is 0.0453

3 0
3 years ago
Triangle ABC is a triangle with no equal sides. A new triangle congruent to triangle ABC is to be placed on the plane such that
Margarita [4]

Answer:

9

Step-by-step explanation:

im bad at explaining

6 0
3 years ago
Given f(x)=2a^2b+3a^3b^2+2a^2b^4 what is the degree?
lilavasa [31]
We have the following function:
 f (x) = 2a ^ 2b + 3a ^ 3b ^ 2 + 2a ^ 2b ^ 4
 We note that the function depends on x because it is f (x).
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 Therefore we can assume that the function is constant, since:
 a = constant
 b = constant
 Therefore, the degree of the function is zero
 Answer:
 
The function is zero degree.
7 0
3 years ago
Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carriers of the disease, th
LuckyWell [14K]

Answer:

Step-by-step explanation:

Given that Tay-Sachs disease is a genetic disorder that is usually fatal in young children. If both parents are carriers of the disease, the probability that each of their offspring will develop the disease is approximately 0.25.

Let X be the no of children having this disease out of 4 occasions

Then X has two outcomes and each trial is independent of the other trial

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a) P(X=4) = 4C4 (0.25)^4 = 0.003906

b) P(X=1) = 4C1 (0.25)(0.75)^3\\= 0.4219

c) P(4th child/3 children did not) = 0.25 since independent.

4 0
3 years ago
The probability of an event is 1. What do you know about the event?
Harrizon [31]

Answer:  A probability of 1 means the event is certain to happen.  A probably of zero means the event is certain not to happen.

3 0
3 years ago
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