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2 years ago

½ is the same as 0.5 and the ratio of _____.

1 answer:

4 0

1/2 IS the same as 0.5. Ratio is fairly easy. an example is 5/6. The ratio would be 5:6. Therefore 1/2 in ratio would be 1:2

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Please help me.......... only 32,and 33

kupik [55]

Answer:

Step-by-step explanation:

Step 1 : Draw PQ = 6cm

Step 2 : Construct 60 degree at Q. [Given PQR = 60=> Q = 60 ]

Step 3 : Take 5 cm on compass and mark 5cm on the 60 degree

line constructed at Q.

Step 4 : The arc of 5cm and 60 degree line meets is the point R.

[Given QR = 5cm ]

Step 5 : Given PQ || SR so construct a 120° at R ,

because ∠PQR and ∠QRS are supplementary angle.

[ ∠PQR + ∠QRS = 60 + 120 = 180° ]

Step 6 : At P , take 6.5 cm on compass and mark on the line drawn in

Step 5, to get S. [ Given PS = 6.5 ]

Given adjacent sides : 4.8 and 4.2

And it is a rectangle.

Step 1 : construct AB = 4.8 cm

Step 2 :At A and B construct 90 degree

Step 3: On the compass take 4.2cm and mark on the 90degree lines

from A and B.

Step 4 : Mark that as C and D respectively.

Step 5 : Join CD

8 0

3 years ago

Three salesmen work for the same company, selling the same product. And, although they are all paid on a weekly basis, each sale

Katarina [22]

Answer:

12 sales

Step-by-step explanation:

Let x represent the number of sales each man had.

For Salesman A, he earns $65 per sale; this is 65x.

For Salesman B, he earns $40 per sale; this is 40x. We also add to this his weekly salary of $300; this gives us 40x+300.

Since their pay was equal, set the two expressions equal:

65x = 40x+300

Subtract 40x from each side:

65x-40x = 40x+300-40x

25x = 300

Divide both sides by 25:

25x/25 = 300/25

x = 12

4 0

2 years ago

A 2x2 square is centered on the origin. It is dilated by a factor of 3. What are the coordinated of the vertices of the square?

Alexxx [7]

Answer:

The vertices are:

A' = (-3, -3)

B' = (3, -3)

C' = (3, 3)

D' = (-3, 3)

The ratio of area of larger square to smaller square is 9:1

Step-by-step explanation:

Given:

A 2 x 2 square is centered at the origin.

So, the center of the square is (0, 0)

Since it is 2 x 2 square, the side of the square is 2 units.

So, the vertices of the 2 x 2 square are A (-1, -1), B(1, -1), C(1. 1), D(-1, 1)

The above square is dilated by a factor of 3.

Let's name the dilated square A'B'C'D'

To find the coordinates of the vertices of dilated square, we need to multiply each vertices of ABCD by 3.

A(-1, -1) = 3(-1, -1) = A'(-3, -3)

B(1, -1) = 3(1, -1) = B'(3, -3)

C(1, 1) = 3(1, 1) = C'(3, 3)

D(-1, 1) = 3(-1, 1) = D'(-3, 3)

To find the area of the small square

the side of the small square is 2 units

so the are of the small square is $2^2$ = 4 square units

To find the area of the larger square

lets find the side AB of the square using distance formula

=> $\sqrt{(x_2 -x_1)^2 +(y_2-y_1)^2}$

=> $\sqrt{(3 - (-3))^2 +(-3 - (-3))^2}$

=> $\sqrt{(3 +3)^2 +(-3 +3)^2}$

=> $\sqrt{(6)^2 +(0)^2}$

=> $\sqrt{36}$

=>6

AB =6 units

In a square all the sides will be equal

Now the area of the larger square will be

$6^2$

36 square units

The ratio of larger square to smaller square is

=>36 : 4

=>9 : 1

5 0

3 years ago

Explain in words what mistake you made and how will correct it. in a group of 20 children,there were 8 girls. which is the ratio

Nataly_w [17]

Well first do 20 children minus 8 girls to find how many boys there are:
20-8=16
So there are 16 boys. Therefore we can write the ratio of girls to boys as:
8/16
Then we can simplify this ratio by dividing it by 8 to get:
1/2
So the answer is the ratio of girls to boys in the group in simplest form is 1/2.

7 0

3 years ago

Classify each pair of angels listed below as adjacent or vertical.

Stolb23 [73]

Answer:

ntersecting lines DA and CE.

To find:

Each pair of adjacent angles and vertical angles.

Solution:

Adjacent angles are in the same straight line.

Pair of adjacent angles:

(1) ∠EBD and ∠DBC

(2) ∠DBC and ∠CBA

(3) ∠CBA and ∠ABE

(4) ∠ABE and ∠EBD

Vertical angles are opposite angles in the same vertex.

Pair of vertical angles:

(1) ∠EBD and ∠CBA

(2) ∠DBC and ∠EBA

5 0

3 years ago