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3 years ago

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An online furniture store sells chairs and tables. Each day, the store can ship no more than 27 pieces of furniture. Write an in

equality that could represent the possible values for the number of tables sold, t, and the number of chairs sold, c, that would satisfy the constraint.

1 answer:

12345 [234]3 years ago

3 0

Answer:

c + t ≤ 27

Step-by-step explanation:

The online furniture store can ship not more than 27 pieces of chairs and tables each day.

If the possible number of chairs they can ship each day is represented by c and the possible number of tables they can ship each day is represented by t, then the inequality equation can be written as

(c + t) ≤ 27. (Answer)

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3 years ago

Read 2 more answers

Sams credit card balance is less than -$36. Does Sam owe more or less than $36

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He owes more.

He has LESS than -36. So he getting further from zero.

So he could have -40 or something because that's less money than -36.

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Please help asap, will mark Brainliest xoxo

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Answer/Step-by-step explanation:

Given, $b(x) = (\frac{6}{7})^{x}$

The table for the function are:

When x = -2

$b(-2) = (\frac{6}{7})^{-2}$

$b(-2) = \frac{1}{(\frac{6}{7})^{2}}$

$b(-2) = \frac{1}{(\frac{36}{49})}$

$b(-2) = 1*\frac{49}{36}$

$b(-2) = \frac{49}{36}$

When x = -1

$b(-1) = (\frac{6}{7})^{-1}$

$b(-1) = \frac{1}{(\frac{6}{7})}$

$b(-1) = 1*\frac{7}{6}$

$b(-2) = \frac{7}{6}$

When x = 0

$b(0) = (\frac{6}{7})^{0}$

$b(0) = \frac{6^0}{7^0}$

$b(0) = \frac{1}{1}$

$b(0) = 1$

When x = 1

$b(1) = (\frac{6}{7})^{1}$

$b(1) = \frac{6}{7}$

When x = 2

$b(2) = (\frac{6}{7})^{2}$

$b(2) = \frac{6^2}{7^2}$

$b(2) = \frac{36}{49}$

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3 years ago