That's Edgenuity ? maybe I can help
AD || BC
<span>• AB = CD </span>
<span>• ∠BAD = ∠CDA (a given condition ∵ ABCD is an isosceles trapezium) </span>
<span>The diagonals AC and BD create two ∆'s: ∆ABD, and ∆ACD </span>
<span>The two ∆'s are congruent (SAS). </span>
<span>(S): AB = CD </span>
<span>(A): ∠BAD = ∠CDA
</span><span>(S): AD = DA (common side) </span>
<span>
The corresponding sides of the two ∆'s, BD and AC, are also congruent. </span>
<span>(the two diagonals of the trapezium/trapezoid)
</span>
E= 9 because you have to distribute -3.6 to E and -4
Total number of coins in question = 275
Number of quarters among the total coins = 120
Then
Remaining number of coins = 275 - 120
= 155
Percentage of coins that are nickel = 20%
Then
Number of coins that are nickel = (20/100) * 155
= 155/5
= 31
Remaining number of coins = 155 - 31
= 124
Ratio of dimes to pennies = 1:3
Let us assume the common ratio to be = x
Then
x + 3x = 124
4x = 124
x = 124/4
= 31
So
The number of pennies = 3 * 31
= 93
From the above deduction we can conclude that there are 93 pennies. The correct option among all the options given in the question is option "C".
