x+(x+2)=116. Simplify that to 2x+2=116, subtract 2 from both sides to get 2x=114, and then divide both sides by 2 to get x=57. That would be the first integer, so the second would then be 59. So there's your answer: The two consecutive odd integers are 57 and 59.Answer:
Step-by-step explanation:
Answer:
y=7x+3
Step-by-step explanation:
Hi there!
We are given the equation y=7x-5 and we want to find the equation of the line that is parallel to it, and contains the point (4,31)
First, let's find the slope of y=7x-5, since parallel lines have the same slopes
The line y=7x-5 is written slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
Since 7 is in the place of where m is, the slope of the line is 7
It's also the slope of the line parallel to it.
We can substitute 7 as m into the formula y=mx+b for our new line:
y=7x+b
Now we need to find b
Since the equation will pass through the point (4, 31), we can use it to solve for b; substitute 31 as y and 4 as x
31=7(4)+b
Multiply
31=28+b
Subtract 28 from both sides
3=b
Substitute 3 as b
y=7x+3
Hope this helps!
Answer:
a(10) = 170
Step-by-step explanation:
Given that,
The nth term fo the sequence is :
a(n) = n² + 7n
We need to find the 10th term of the sequence.
Put n = 10 in the above sequence,
a(10) = (10)² + 7(10)
= 100 + 70
= 170
So, the 10th term of the sequence is 170.
Let's determine the measures of the angles formed by two heights of an equilateral triangle.
