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umka21 [38]
3 years ago
15

​(5 – 6i) – (3 – 2i) solve the equation.

Mathematics
1 answer:
Natalija [7]3 years ago
6 0

Step-by-step explanation:

(5 – 6i) = -(3 – 2i)

5-6i= -3+2i

8=8i

i=1

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Answer:

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Step-by-step explanation:

Let's call C the amount in credit that Ignatius had, and D the amount in debits that Ignatius had during the month.

We know that the initial amount in his account was 124.82, while the final balance was 659.27. The final amount is equal to the initial amount plus the amount of credits minus the amount of debits; in formula:

659.27 = 124.82+(C-D)

Re-arranging the equation, we find:

C-D=659.27-124.82=534.45\\C=D+534.45

Which means that Ignatius had $534.45 more in credit than in debits, which corresponds to option C.

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