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2 years ago

1.5.3 Quiz: Literal Equations and Formulas

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

3 0

Answer:

c = F-32; 68-32 = 36°C.

Step-by-step explanation:

the real conversation equation is f = 9/5 C + 32. but for the sake of this problem we are ignoring the coefficient.

so it's 36°C

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3 years ago

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Simplify the equations:8(y-x)-2(x-y) HELP ASAP!!

SVEN [57.7K]

Answer:

simplified equation is 10y-10x

Step-by-step explanation:

8(y-x) -2(x-y)

multiple 8 and 2 by the corresponding parentheses

8y-8x -2x +2y

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3 years ago

Your store cost on a dozen eggs is $0.75, and your retail price is $2.99. You are having a promotion that discounts the

posledela

Answer:

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Step-by-step explanation:

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3 years ago

webassign If a snowball melts so that its surface area decreases at a rate of 6 cm2/min, find the rate at which the diameter dec

drek231 [11]

Answer:

The answer is $\frac{3}{10\pi } cm/min$

Step-by-step explanation:

Assuming the snowball is a perfect sphere, then if A denotes the surface area and D the diameter then:

$A=4\pi r^{2} = 4\pi (\frac{D}{2} )^{2} =\pi D^{2}$

Differentiating wrt r we have:

$\frac{dA}{dD} =2\pi D$

We are told that $\frac{dA}{dt}= -6$ and we want to find $\frac{dD}{dt}$

By the chain rule we have:

$\frac{dA}{dD}=\frac{dA}{dt}.\frac{dt}{dD}=\frac{\frac{dA}{dt} }{\frac{dD}{dt} }$

∴ $2\pi D=-\frac{6}{\frac{dD}{dt} }$

∴ $\frac{dD}{dt}=-\frac{6}{2\pi D}$

When D=10 then

$\frac{dD}{dt} =-\frac{6}{10*2\pi } =-\frac{3}{10\pi }$

The sign (-) shows that the D is decreasing.

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3 years ago

The scatter plot shows a correlation between the years and the rainfall in centimeters in Tennessee.

nataly862011 [7]

Answer:

Step-by-step explanation:

The actual values are shown on the given graph as blue points.

The line of regression is shown on the given graph as the red line.

From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.

⇒ Difference = 50 - 43 = 7 cm

In 2000, the actual rainfall was 7 centimeters below what the model predicts.

From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.

⇒ Difference = 44 - 40 = 4 cm

In 2003, the actual rainfall was 4 centimeters above what the model predicts.

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2 years ago