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Degger [83]
3 years ago
13

Victoria is 4 years older than her neighbor. The sum of their ages is no more than 14 years.

Mathematics
2 answers:
quester [9]3 years ago
5 0

X+x+4<=14 is the correct answer took the test hope this helps:)

elena55 [62]3 years ago
3 0
(x+4)+v<=14

Would be the inequality you need, hope this helps ;D
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Please help me asap!!!
Advocard [28]

Answer:

g=64.8 meters

Step-by-step explanation:

\frac{26.1}{24.3} = \frac{69.6}{g}

69.6×24.3= 26.1×g

1,691.28=26.1g

64.8=g

g=64.8

Hope this helps! :)

Oh, I got the order of the ratios wrong, I'm sorry.

I just corrected it.

6 0
3 years ago
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Helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), and Radon (Rn) have a completely filled outer electron shell and a
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Answer:

The answer would be 1.

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3 years ago
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Please help me ASAP <br> Please help <br> No links please
lisov135 [29]

Answer:

a is height

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Step-by-step explanation:

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3 years ago
Joseph drives 125 miles in 2 1/2 hours. At the same rate , how far will he be able to travel in 6 hours ?
Mariana [72]

Answer:

Step-by-step explanation:

300 miles

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8 0
3 years ago
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the population of collin county, which follows the exponential growth model, increased from 491,675 in 2000 to 782,341 in 2010.
CaHeK987 [17]

Applying the formula for the exponential growth model, the growth rate is  0.046447277776453351798354258063923

the exponential growth is a data pattern that illustrates an increase over time by generating an exponential function curve.

The exponential growth model can be expressed as:

P(t) = P(0) x e^(k.t)

Where:

P(t) = Value at time t

P(0) = Initial value

k = growth rate

Information from the problem:

P(0) = 491,675

P(t) = 782,341

t = 2010 - 2000 = 10 years

Substitute the data into the formula:

782,341 = 491,675 x e^{10k}

e^{10k} = 782,341 / 491,675

10 k . ln e = ln (782,341 / 491,675)

10 k = 0.46447277776453351798354258063923

k = 0.046447277776453351798354258063923

Read more about the exponential growth model here:

brainly.com/question/14973088

#SPJ4

8 0
1 year ago
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