Hello,
Answer C
Be carefull
A: is (gof)(x)=g(f(x))=g(x^8)=6x^8-14
C: fog(x)=f((g(x))=f(6x-14)=(6x-14)^8
Given sets A = {t, u, v, w, x, y, z} and B = {p, q, r, s, t, u}. Find A and B
alexgriva [62]
Answer:
okay so
so we have A and B = {t,u}
Answer:
- Length = 43 inches
- Width = 12 inches
Step-by-step explanation:
Perimeter of a rectangle = 2 * ( L + W)
The length of a rectangle is 5 inches less than 4 times the width.
Assume the width is x. Length is:
4x - 5
Equation is therefore:
2 * (4x - 5 + x) = 110
4x - 5 + x = 110/2
5x - 5 = 55
5x = 55 + 5
x = 60/5
x = 12 inches
If width is 12 inches, then length is:
= 4x - 5
= 4 * 12 -5
= 43 inches
From the given table, the positive sign connote deposit while the negative sign connotes withdrawal.
If the account shows a zero balance after 4 weeks, we will take the sum of all deposits and withdrawals for the first four weeks and equate to zero as shown:
Open the parenthesis:
Subtract 70 from both sides
Hence the value of p if the account shows a zero balance after 4 weeks is -70
Learn more on deposits and withdrawals here: brainly.com/question/11443019
4. You would need to set up equations. Two per problem. So 5x+2s=98. And 9x+2s=154. Then you would multiply one of them by a negative one to make the 2 student tickets cancel out. I would use the top one. So it turns to -5c-2s=-98. The -2c and 2c cancel out. You put the rest together to get 4X=56. And 56/4 is 14. So the senior tickets (X) are 14$. You would then replace X with fourteen one of the original equations. Again I'm going to use the first one. So 5(14)+2c=98. 5x14 is 70. Subtract 70 from both sides to get 2c=28. Divide both sides by 2 to get C=14. So the student tickets are 14$ and the seniors are also 14$.
5. Same thing on this one. Two equations. 8h+7i=84 and 3h+1i=25. Like going to multiply the second equation by -7 so the i's will cancel out to get -21h-7i=-175. So you will end up with -13h=-91. Divide both sides by -13 to get H=7. Replace H in one of the equations. I'll use second one. So 3(7)+1i=25. 3x7=21 so subtract 21 from both sides to get i=4. So the ivy is 4$ and the hostas are 7$.
Hope that helped a little bit!