Ask question

Ask question

All categories

3 years ago

6

The Thompson family and the Evans family each used their sprinklers last summer. The water output rate for the Thompson family's

sprinkler was 20 L per
hour. The water output rate for the Evans family's sprinkler was 25 L per hour. The families used their sprinklers for a combined total of 55 hours, resulting in a
total water output of 1225 L. How long was each sprinkler used?

2 answers:

maw [93]3 years ago

8 0

Answer:

Thompson 30hrs

Evans 25hrs

Step-by-step explanation:

Just take 25 by 25 and 30 by 20

AlexFokin [52]3 years ago

6 0

Answer:

Sprinkles

Step-by-step explanation:

You might be interested in

Im really bad at this haha

expeople1 [14]

The correct answer is B

5 0

3 years ago

Read 2 more answers

What does 1/10 of 3000 equal?

arsen [322]

Answer:-
1/10×3000
=300

4 0

3 years ago

Read 2 more answers

SinA=√1-x÷√1+X<br> Find the value of cosA

Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = $\sqrt{1} - x$

Hypotenuse = $\sqrt{1} + x$

Let's find the adjacent side using the Pythagorean theroem

$(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2$

$1 + x^2 = 1 - x^2 + x^2$

$x = \sqrt{\frac{1 + x^2}{1 -x^2} }$

cos A = x/hypotenuse

$cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}$

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

6 0

1 year ago

5 and 4 sevenths times negative 2 and 2 fifths

Dimas [21]

Answer:

3/2

Step-by-step explanation:

ugygv

6 0

2 years ago

I need help with this ASAP plzzzzz

miss Akunina [59]

Answer:

23. $\frac{4\sqrt{3} }{3}$

24. $\frac{7\sqrt{3}}{3}$

25. $6\sqrt{3}$

26. $\frac{10\sqrt{3} }{3}$

27. $14$

28. $4\sqrt{3}$

Step-by-step explanation:

To solve these i used SOHCAHTOA

$sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}$

23.

Find the missing side using Tangent

$tan(30)=\frac{x}{4}$

$4*tan(30)=x$

$\frac{4\sqrt{3} }{3}$

24.

Find the missing side using Tangent

$tan(30)=\frac{x}{7}$

$7*tan(30)=x$

$\frac{7\sqrt{3}}{3}$

25.

Find the missing side using Tangent

$tan(30)=\frac{x}{18}$

$18*tan(30)=x$

$6\sqrt{3}$

26.

Find the missing side using Tangent

$tan(30)=\frac{x}{10}$

$10*tan(30)=x$

$\frac{10\sqrt{3} }{3}$

27.

Find the missing side using Tangent

$tan(30)=\frac{x}{14\sqrt{3} }$

$(14\sqrt{3}) *tan(30)=x$

$14$

28.

Find the missing side using Tangent

$tan(30)=\frac{x}{12}$

$12*tan(30)=x$

$4\sqrt{3}$

5 0

3 years ago