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sp2606 [1]
3 years ago
13

Help please. Brainleist goes to best answer

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0
Thank you very much Maz.
I really appreciate it :)
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How do I factorise 2t^2 + 5t +2
alekssr [168]
2t^2+5t+2\\\\a=2;\ b=5;\ c=2\\\\\Delta=b^2-4ac;\ if\ \Delta > 0\ then\ t_1=\frac{-b-\sqrt\Delta}{2a}\ and\ t_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=5^2-4\cdot2\cdot2=25-16=9;\ \sqrt\Delta=\sqrt9=3\\\\t_1=\frac{-5-3}{2\cdot2}=\frac{-8}{4}=-2;\ t_2=\frac{-5+3}{2\cdot2}=\frac{-2}{4}=-\frac{1}{2}\\\\2t^2+5t+2=2(x+2)(x+\frac{1}{2})
5 0
3 years ago
HELP! Ill vote brainliest and 60 pts is on the line!
WITCHER [35]

Answer:

2

Step-by-step explanation:

2x^2-8x+7=0\\\\

a=2

b=-8

c=7

\frac{8+ \sqrt{16-4(2)(7)} }{4}

4±\sqrt{2} /2

4 0
3 years ago
Read 2 more answers
Using L’hopital’s rule please I need this ASAP Is due today!!!!!!!!!
Gelneren [198K]

Answer:

See below.

Step-by-step explanation:

You differentiate  top and bottom of the fraction until substitution gives you a value.

I can do the third one for you:

Lim x --> 0 of sin2x / sin3x

= lim x --> 0 of 2 cos2x / 3 cos 3x

= 2 cos 0 / 3 cos 0

= 2/3.

Limit as x--> 0  of (e^x - (1 - x) / x

= limit as x --> 0 of e^x + x - 1 / x

=  lim (e^x + 1) / 1

= 1 + 1 / 1

= 2.

limit as x-->  00  of  3x^2 - 2x +  1/ (2x^2 + 3)

= limit as x --> 00 of  6x - 2 / 4x     ( 00 = infinity)

Applying l'hopitals rule again:

limit is 6 / 4 =  3/2.

Limit  as x --> 00 of (ln x)^3 / x

= limit  3 (Ln x)^2 ) / x

= limit of  6 ln x / x

= limit  6 / x

= 0.

We had  to apply l'hopitals  rule 3 times here,

5 0
3 years ago
Point P is the circumcenter of △ABC. List any segment(s) that are congruent to BP.
Vikki [24]
<h3>Answers: PA and PC</h3>

Explanation:

Segments PB, PA and PC are all radii of the same circle. We call this circle the circumcircle, with point P as the center of this circle.

To determine the location of P, we construct at least two perpendicular bisectors as the diagram shows. Segments PR, PS and PT are perpendicular bisectors of AB, AC, and BC in that order.

8 0
3 years ago
What is 218,375 in expanded form
Kazeer [188]
200000+1000+8000+300+70+5
5 0
3 years ago
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