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kolbaska11 [484]
3 years ago
13

Can somebody please help I don't understand how to do this​

Mathematics
1 answer:
boyakko [2]3 years ago
7 0

Answer:

hbsbipynoibnrioudjtoudjtuodjoudk

Step-by-step explanation:

linylnutdbitdiltcicyrkdvutodubtuodjtohtsuodhuthuodtjutodhodutohutdhusotohdtidgidgtidgtigdtuhothuodtohudtuodthhoudthoudtuohtd

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Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
Solve the inequality
AnnyKZ [126]

x+15\geq9\qquad\text{subtract 15 from both sides}\\\\\boxed{x\geq-6}

7 0
2 years ago
Q2: What is the radius? Because this is an approximation use 3.14 as pi. Round to
bija089 [108]

Answer:

r=11 m

Step-by-step explanation:

Too lazy to explain:

πr²h=v

3.14*r²*12=4560

r²≈121

r is 11 m

4 0
2 years ago
Read 2 more answers
X = ????????? Geometry
bazaltina [42]

Answer:

\boxed{x = 6}

Step-by-step explanation:

Using Chord-Chord Power theorem:

=> (2)(x) = (4)(3)

=> 2x = 12

Dividing both sides by 2

=> x = 6

7 0
3 years ago
Area of Circles - Item 20636
Dennis_Churaev [7]
12.7388535, so about 13 would be the radius
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