<u>Given</u>:
Given that the triangular prism with height 10 inches.
The side lengths of the base of the triangle are 12 inches, 13 inches and 5 inches.
We need to determine the surface area of the prism.
<u>Surface area of the prism:</u>
The surface area of the prism can be determined using the formula,
where b is the base and h is the height of the triangle.
s₁, s₂, s₃ are the side lengths of the triangle and
H is the height of the prism.
Substituting b = 12, h = 5, s₁ = 12, s₂ = 5, s₃ = 13 and H = 10 in the above formula, we get;
Thus, the surface area of the triangular prism is 360 square inches.
Hence, Option b is the correct answer.
(X-5)2+3(X-5)+9 = 0
let expand the equation
(x)x2-(5)x2 + 3(x)-3(5) + 9 = 0
2x-10+3x-15+9=0
collect like terms
2x+3x-10-15+9 =0
5x-10-6 =0
5x-16=0
5x=0+16
5x=16
divide both side by 5 we have
x=16/5
<span>10.
if we were to
subsitute the points and graph the equation we would notice that the
shape is the same for both: a 45 degree angle line that goes upleft and
up right
the graph of y=|x| looks like a right angle corner that is facing up that is ballancing on the point (0,0)
the
graph of y=|x|-4 is the same except that the graph is shifter 4 units
to the right ie. the point ofo the graph/rightangle is on point (4,0)
14.
slope intercept form which is y=mx+b
m=slope b=y intercept
m=4/3
y=4/3x+b
one given solution/point is (9,-1)
one solution is x=9 and y=-1 so subsitute and solve fo b
-1=4/3(9)+b
-1=36/3+b
-1=12+b
subtract 12 from both sides
-11=b
the equation si y=4/3x-11
see which one converts to the correct form
after trial and error we find that y-1=4/3(x-9) is the answer
</span>
