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Sloan [31]
3 years ago
8

If overapplied or underapplied overhead is material, it should be disposed of by allocating it to: Select one: a. Cost of goods

sold and finished goods inventory. b. Finished goods inventory and work in process inventory. c. work in process inventory, finished goods inventory, and cost of goods sold. d. work in process inventory. e. Raw materials inventory, work in process inventory, and finished goods inventory.
Business
1 answer:
noname [10]3 years ago
4 0

If overapplied or underapplied overhead is material, it should be disposed of by allocating it to Cost of goods sold and finished goods inventory.

Option A

Explanation:

Fixed Overhead expenses are allotted to on the basis of predetermined overhead rate to each unit. Sometimes overhead expenses estimated and actually incurred have differences.

If the actual overhead is more than overhead applied to production than it is called under applied overhead. When actual overhead is less than applied overhead than it is called over applied overhead.

Balance of difference of these overhead is debited or credited to Cost of goods sold of company.

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The following information relating to a company's overhead costs is available. Col1 = Actual total variable overhead, Actual tot
Free_Kalibri [48]

Answer:

A) $2,000 favorable

Explanation:

Actual total variable overhead = $ 73,000

Actual total fixed overhead = $ 17,000

Budgeted variable overhead rate per machine hour = $ 2.50

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3 years ago
An organization's critical application is required to be continuously available, with only a few minutes' per month of downtime
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4 years ago
the area of a rectangle is 600 cm2 and its breadth is two-third of its length find the length and breadth of the rectangle​
alexandr1967 [171]

Given:

Area of a rectangle is 600 \text{cm}^2.

Breadth is two-third of its length.

To find:

The length and breadth of the rectangle​ .

Solution:

Let x cm be the length of the rectangle.

Then, Breadth or width of the rectangle = \dfrac{2}{3}x cm

Area of a rectangle is

Area=Length \times Breadth

600=x \times \dfrac{2}{3}x

600=\dfrac{2}{3}x^2

Multiply both sides by 3.

1800=2x^2

Divide both sides by 2.

900=x^2

Taking square root on both sides.

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Length = 30\text{ cm}

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Therefore, the length of the rectangle is 30 cm and the breadth is 20 cm.

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