3x- 5y=7 5x- 2y=- 1 X=? Y=?

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

8 0

3 years ago

Can you please help? I know the one I chose is correct.

AleksandrR [38]

I believe you are right :) because they are the same

7 0

2 years ago

Read 2 more answers

J^2 over 2j times 2j over 3g

Serhud [2]

Answer:

D

Step-by-step explanation:

given $\frac{j^2}{2j}$ × $\frac{2j}{3g}$

the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as

= $\frac{j^2}{3g}$ → D

5 0

3 years ago

2. What are the solutions to the quadratic equation

Svetlanka [38]

Answer:

The answer is x=5 and x=−5

x² - 25 = 0

(x-5)(x+5)=0

x²-5x+5x-25=0

x-5=0 x+5=0

x=5 or x=-5

8 0

2 years ago

identify the amplitude and period of the function then graph the function and describe the graph of G as a transformation of the

mrs_skeptik [129]

Given the function:

$g(x)=cos4x$

Let's find the amplitude and period of the function.

Apply the general cosine function:

$f(x)=Acos(bx+c)+d$

Where A is the amplitude.

Comparing both functions, we have:

A = 1

b = 4

Hence, we have:

Amplitude, A = 1

To find the period, we have:

$\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}$

Therefore, the period is = π/2

The graph of the function is shown below:

The parent function of the given function is:

$f(x)=cosx$

Let's describe the transformation..

Apply the transformation rules for function.

We have:

The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.

ANSWER:

Amplitude = 1

Period = π/2

Transformation = horizontal compression.

8 0

10 months ago

3x- 5y=7 5x- 2y=- 1X=? Y=?