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3 years ago

What number is 1426/7% of 77?

Mathematics

2 answers:

Fantom [35]3 years ago

4 0

<span>≈ 264.564007421, assuming that by "1426/7% of 77" you mean 7% of 77 divided by 1426.</span>

Sholpan [36]3 years ago

3 0

I hope this helps you

?.1426/7/100=77

?.1426.100=7.77

?=539/142600

?=3,7

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A circle has a radius of 5 in. A central angle that measures 150° cuts off an arc.

Slav-nsk [51]

Answer:

Part 1) The exact value of the arc length is $\frac{25}{6}\pi \ in$

Part 2) The approximate value of the arc length is $13.1\ in$

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference of a circle is equal to

$C=2\pi r$

we have

$r=5\ in$

substitute

$C=2\pi (5)$

$C=10\pi\ in$

step 2

Find the exact value of the arc length by a central angle of 150 degrees

Remember that the circumference of a circle subtends a central angle of 360 degrees

by proportion

$\frac{10\pi}{360} =\frac{x}{150}\\ \\x=10\pi *150/360\\ \\x=\frac{25}{6}\pi \ in$

step 3

Find the approximate value of the arc length

To find the approximate value, assume

$\pi =3.14$

substitute

$\frac{25}{6}(3.14)=13.1\ in$

7 0

3 years ago

How do you rewrite equations in slope intercept form ?

PIT_PIT [208]

Slope intercept form is y = mx+b, so you can see that you set the equation equal to y. So if the equation is 2y+3x=6, then you solve for y to put it in slope intercept form.
2y + 3x = 6
2y = -3x + 6
y = (-3/2)x + 3

Keep in mind that the term with the x has to be before the constant, so it can't be y = 3 -(3/2)x

And by the way m is the slope and b is y-intercept, so in <span>y = (-3/2)x + 3, -3/2 is slope and (0,3) is y-intercept</span>

3 0

4 years ago

Find the area of the shaded region. The radius of the large circle is 10 m. Round answer to the nearest hundredth.

vivado [14]

Answer:

hello the figure related to your question is missing attached below is the missing figure

answer : 157.08 m^2

Step-by-step explanation:

Calculate the area of the shaded area

= Area of the large circle - Areas of the small circles

= (( $\frac{\pi }{4}$ ) * D^2) - 2( ( $\frac{\pi }{4}$ ) * d^2 ) given that the small circles are congruent

= (( $\frac{\pi }{4}$ ) * 20^2 ) - 2 ( ( $\frac{\pi }{4}$ ) * 10^2 )

= 314.16 - 157.08

= 157.08 m^2

8 0

3 years ago

Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,

vladimir1956 [14]

Answer:

(a) $C(6,0) = 1$ , $C(6,1) = 6$ , $C(6,2) = 15$ , $C(6,3) = 20$ , $C(6,4) = 15$ , $C(6,5) = 6$ , $C(6,6) = 1$ .

(b) $C(7,0) = 1$ , $C(7,1) = 7$ , $C(7,2) = 21$ , $C(7,3) = 35$ , $C(7,4) = 35$ , $C(7,5) = 21$ , $C(7,6) = 7$ , $C(7,7)=1$ .

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

$C(n,k) = \frac{n!}{k!(n-k)!}$

where the symbol $n!$ is the factorial and means

$n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n$ .

By convention 0!=1. The most important property of the factorial is $n!=(n-1)!\cdot n$ , for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

$C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1$

$C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20$

$C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15$

$C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6$

$C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1$ .

(b) The explanations to the solutions is just the calculations.

$C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1$

$C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7$

$C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21$

$C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35$