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erica [24]
3 years ago
11

Find the value of Y

Mathematics
2 answers:
TEA [102]3 years ago
7 0
-6y + 14 + 4y = 32
-2y + 14 = 32
- 14
-2y = 18
÷ -2
y = -9

So your answer is B. -9. I hope this helps!
Nadya [2.5K]3 years ago
6 0
The answer is D.

this is unnecessary because i have to have twenty characters<span />
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Write each expression as a product of linear factors 1. X^2+1/2x 2. X^2+2x-3 3. (2x-3)^2 4. X^3+2x^2-19x-20
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Answer:

1. X^2+1/2x = x(x+\frac{1}{2})

2.  X^2+2x-3 = (x-1)(x+3)

3. (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 = (x+1)(x-4)(x+5)

Step-by-step explanation:

Each expression can be written as a product of linear factors as follows

1. X^2+1/2x ⇒ x^{2} + \frac{1}{2}x

x^{2} + \frac{1}{2}x = x(x+\frac{1}{2})

Hence,  X^2+1/2x = x(x+\frac{1}{2})

2. X^2+2x-3 ⇒ x^{2} +2x-3

x^{2} +2x-3 = x^{2} +3x-x-3

x^{2} +3x-x-3 = x(x+3) -1(x+3)

x(x+3) -1(x+3) = (x-1)(x+3)

Hence,  X^2+2x-3 = (x-1)(x+3)

3. (2x-3)^2 ⇒(2x-3)^{2}

(2x-3)^{2} = (2x-3)(2x-3)

Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ x^{3}+2x^{2} -19x -20

x^{3}+2x^{2} -19x -20  = (x+1)(x^{2} +x-20)

First,

x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)

∴ (x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)

Hence, X^3+2x^2-19x-20 = (x+1)(x-4)(x+5)

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