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3 years ago

15

F(x)= 10x+6 and g(x)=

x - 6}{10} " alt=" \frac{x - 6}{10} " align="absmiddle" class="latex-formula">

1 answer:

Evgesh-ka [11]3 years ago

7 0

F( g(x) ) = 10( [x-6] ) + 6 = 10x - 60 + 6 = 10x - 56

Please do the other problem in a similar fashion. For "x" in g(x), substitute "10x+6."

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2(x-+2)+4=6x-4(-1+x)

sertanlavr [38]

2x-4+4=6x+4-4x

2x=2x+4

c there is no solution

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2 years ago

Read 2 more answers

If x = -6, which inequality is true?

igomit [66]

Answer:

C. 1 - 2x > 13

Step-by-step explanation:

you just substitute

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3 years ago

Given DB=42 AD=26 and SAE=52

blsea [12.9K]

Answer:

AC=42

EB=21

BC=26

thats all i know, sorry hope u figure it out

Step-by-step explanation:

4 0

2 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

3 years ago

Which statement correctly explains the association of the scatterplot

Blababa [14]

Answer:

B. Since the y - values decrease as the x - values increase the scatter plots show a negative association.

Step-by-step explanation:

A positive association would be the y - values and the x - values both increases.

I hope this helps!

5 0

2 years ago