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3 years ago

There was no more rainfall for the rest of the day.

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

5 0

There’s no exact value listed on this graph, but it would be where the line ends completely on the far right. The rain was fluctuating throughout the day when the graph was going up and down. when the graph completely stops, the rain did too.

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Pls help!!

Ilya [14]

Step-by-step explanation:

Parallel lines have the same slope so they can therefore never touch. Just change the y-int. (Any number as long as it's not the same as the previous)

I.E.:

y = -3x - 12

6 0

3 years ago

If m<9=97 and m<12=114, find each measure.

seropon [69]

Answer:

a. 97

b. 83

c.66

d. 114

e.83

f. 97

g. 114

h.66

i. 83

j. 66

k.83

l.97

m. 114

n. 66

6 0

4 years ago

The Snack Shack solls hamburgers,

lorasvet [3.4K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Use synthetic division to evaluate (3x2 − 6x + 3) ÷ (x − 1). 3x − 9 3x2 − 3x 3x − 3 3x2 − 6

Viefleur [7K]

Answer:

$\frac{\left(3x^2-6x+3\right)}{\left(x-1\right)3x-93x^2-3x^3x-33x^2-6}: -\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}$
$\frac{3x^2-6x+3}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}$
$\frac{3\left(x-1\right)^2}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}$
$\frac{3\left(x-1\right)^2}{-3\left(x^4+41x^2+x+2\right)}$
$\frac{\left(x-1\right)^2}{-\left(x^4+41x^2+x+2\right)}$
$-\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}$

3 0

2 years ago

What is the slope of the line?

kolbaska11 [484]

Answer:

im not very sure but i think its A or C

4 0

3 years ago

Read 2 more answers