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Sloan [31]
3 years ago
15

There was no more rainfall for the rest of the day.

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
5 0
There’s no exact value listed on this graph, but it would be where the line ends completely on the far right. The rain was fluctuating throughout the day when the graph was going up and down. when the graph completely stops, the rain did too.
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Please help me thanks
Lynna [10]

Answer:

If we look at ΔBDH, we notice that m∠BHG has to be 108 - 36 - 39 = 105°. Because x and ∠BHG are a linear pair we know that x = 180 - ∠BHG = 180 - 105 = 75°.

7 0
3 years ago
Read 2 more answers
What are the solutions to the system of equations? y=x2−5x−6 y=2x−6
Leya [2.2K]

Answer:

I graphed both equations to find the solutions.

Step-by-step explanation:

When x is 0, y is -6. When x is 7, y is 8.

x = 0 and 7

4 0
3 years ago
Read 2 more answers
Drag each tile to the correct box. not all tiles will be used.Chris plans to mulch the border surrounding a rectangular garden i
amm1812

Length (L): 2w + 3

width (w): w

border (b): \frac{1}{4} w

Area (A) = (L + b) * (w + b)   <em>NOTE: This is assuming the width also has a border</em>

              = (2w + 3 + \frac{1}{4} w) * (w + \frac{1}{4} w)

              = (2\frac{1}{4} w + 3)(1\frac{1}{4} w)

              = (\frac{9}{4} w + 3)(\frac{5}{4} w)

              = \frac{45}{16} w^2 + \frac{15}{4}w


5 0
3 years ago
Select the correct answer.
tino4ka555 [31]

Answer:

A . The inequality sign always opens up to the larger number.

Step-by-step explanation:

4 0
3 years ago
Solve x2 + 8x = 33 by completing the square. Which is the solution set of the equation? {–11, 3} {–3, 11} {–4, 4} {–7, 7}
NemiM [27]

Answer:

The solution of the equation are 3 , -11

Step-by-step explanation:

* Lets revise how to make the completing square

- The form of the completing square is a(x - h)² + k, where a , h , k

 are constant

- The general form of the quadratic is ax² + bx + c, where a , b , c

 are constant

- To change the general form to the completing square form equate

  them and find the constant a , h , k

* Now lets solve the problem

∵ x² + 8x = 33 ⇒ subtract 33 from both sides

∴ x² + 8x - 33 = 0

- lets change the general form to the completing square

∴ x² + 8x - 33 = a(x - h)² + k ⇒ solve the bracket of power 2

∴ x² + 8x - 33 = a(x² - 2hx + h²) + k ⇒ multiply the bracket by a

∴ x² + 8x - 33 = ax² - 2ahx + ah² + k ⇒ compare the two sides

∵ x² = ax² ⇒ ÷ x²

∴ a = 1  

∴ -2ah = 8 ⇒ substitute the value of a

∴ -2(1)h = 8 ⇒ -2h = 8 ⇒ ÷ (-2)

∴ h = -4

∵ ah² + k = -33 ⇒ substitute the value of a and h

∴ (1)(-4)² + k = -33

∴ 16 + k = -33 ⇒ subtract 16 from both sides

∴ k = -49

∴ x² + 8x - 33 = (x + 4)² - 49

* Now lets solve the completing square

∵ (x + 4)² - 49 = 0 ⇒ add 49 to both sides

∴ (x + 4)² = 49 ⇒ take square root for both sides

∴ (x + 4) = ± 7

∵ x + 4 = 7 ⇒ subtract 4 from both sides

∴ x = 3

∵ x + 4 = -7 ⇒ subtract 4 from both sides

∴ x = -11

* The solution of the equation are 3 , -11

4 0
3 years ago
Read 2 more answers
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