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3 years ago

Need help pls .......

Mathematics

1 answer:

sukhopar [10]3 years ago

7 0

Answer:

It should be the last one because rigid transformations doesn't change in size just where it is

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Show your work (40 points) ASAP

Alik [6]

Answer:

x=8

The value of z is 49°.

4 0

4 years ago

Solution of this equation sqrt x+10-9=-7

myrzilka [38]

Original equation
√x+10-9 = -7

Isolate
√x+10 = 9-7

√x+10 = 2
 Raise both sides to the second power
 (√x+10)2 = (2)2

 After squaring
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x + 6 = 0

so the answer is x=-6

3 0

3 years ago

Read 2 more answers

The dependent variable, y is 7 more than 1/2 the independent variable, x.

san4es73 [151]

Y=(x/2)+7 as an equation if that is what you are asking

8 0

3 years ago

(I really need help with this because I have no Idea what to do. It's a lot of points and I need to get a good grade on this so

klio [65]

The correlation does not match up with the contents and calories. I’m not sure what you do to determine the correlation.

6 0

3 years ago

A national manufacturer of ball bearings is experimenting with two different processes for producing precision ball bearings. It

lapo4ka [179]

Answer:

A. As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

B. t=-3.144

C. The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

D. P-value = 0.004

E. Reject H0

F. The probability of making a Type I error is equal to the significance level: P(Type I error) = 0.05.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the two processes yield different average errors.

As we are trying to test if the two processes yield different average errors, we are interested in any of the two posibilities: the average error of process A being statistically significant lower or bigger than the average error of Process B. That is why this is a two-tailed test.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

being μ1: average error for Process A and μ2: average error fo Process B.

The significance level is 0.05.

The sample 1, of size n1=12 has a mean of 2 and a standard deviation of 1.

The sample 1, of size n1=14 has a mean of 3 and a standard deviation of 0.5.

The difference between sample means is Md=-1.

$M_d=M_1-M_2=2-3=-1$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1^2}{12}+\dfrac{0.5^2}{14}}\\\\\\s_{M_d}=\sqrt{0.083+0.018}=\sqrt{0.101}=0.318$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-1-0}{0.318}=\dfrac{-1}{0.318}=-3.144$

The degrees of freedom for this test are:

$df=n_1+n_2-1=12+14-2=24$

The critical value for a significance level of 0.05, a two tailed test with 4 degrees of freedom is t=±2.064.

This test is a two-tailed test, with 24 degrees of freedom and t=-3.144, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t$

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the two processes yield different average errors.

5 0

3 years ago