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77julia77 [94]
3 years ago
15

Given that p varies jointly as q and r, and p = 7. when q = 2

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

P = k*q*r

Step-by-step explanation:

P = kqr

7 = k*2*1.5

7 = 3k

k = 7/3

b. P = kqr

= 7/3*4*6

= (7*4*6)/3

= 168/3

= 56

P = 56

c. P = kqr

1 = 7/3*q*3

1 = (7*q*3)/3

1 = 21q/3

Cross product

1*3 = 21q

3 = 21q

q = 3/21

= 1/7

q = 1/7

d. P = kqr

5 = 7/3*8*r

5 = (7*8*r)/3

5*3 = 56r

15 = 56r

r = 15/56

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Can someone help me with this i got the question wrong the first time so its not 7.50
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Step-by-step explanation:

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3 years ago
Eight less than 1/3 a number n is -13
Goryan [66]
1/3n - 8 = -13 <== ur equation
1/3n = -13 + 8
1/3n = - 5
n = -5 * 3
n = -15

check..
1/3(-15) - 8 = -13
-5 - 8 = -13
-13 = -13 (correct)

so the number (n) = -15
3 0
3 years ago
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