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77julia77 [94]
3 years ago
15

Given that p varies jointly as q and r, and p = 7. when q = 2

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
4 0

Answer:

P = k*q*r

Step-by-step explanation:

P = kqr

7 = k*2*1.5

7 = 3k

k = 7/3

b. P = kqr

= 7/3*4*6

= (7*4*6)/3

= 168/3

= 56

P = 56

c. P = kqr

1 = 7/3*q*3

1 = (7*q*3)/3

1 = 21q/3

Cross product

1*3 = 21q

3 = 21q

q = 3/21

= 1/7

q = 1/7

d. P = kqr

5 = 7/3*8*r

5 = (7*8*r)/3

5*3 = 56r

15 = 56r

r = 15/56

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Simply subtract the fail rate from 100; the resulting number is the pass rate. So, if you know that 6 percent of students failed, you would subtract: 100 - 6 = 94 percent is the pass rate for the test.

Step-by-step explanation:

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The cost of insurance can vary wildly between insurance companies. True or False
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Answer:

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Step-by-step explanation:

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3 years ago
On an uphill hike, Ted climbs at a rate of 3 miles an hour. Going down, he runs at a rate of 5 miles an hour. If it takes him 40
telo118 [61]

It takes 40 minutes more going up or 40/60 = 0.67 hours more.

Let us say that:

t = the time required for him running down

t + 0.67 = time required for him running up

 

Since the distance of running up and down must be equal therefore:

(3 miles / hr) * (t + 0.67) = (5 miles / h) * t

3 t + 2.01 = 5 t

2 t = 2.01

t = 1.005 hr

 

So the total length of the hike is:

length = 2 * (5 miles / hr) * (1.005 hr)

<span>length = 10.05 miles</span>

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{This question has been deleted}
stiks02 [169]

Answer:

this question isn't deleted yet

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3 years ago
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A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) afte
Vlad1618 [11]

A quadratic equation is in the form of ax²+bx+c. The time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

The complete question is:

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) after 7 seconds is given by the following, h=2+31t-16t². Find all values of t for which the ball's height is  16 feet. Round your answer(s) to the nearest hundredth.

The time at which the height of the ball is 16 feet can be found by,

h = 2 + 31t - 16t²

16 = 2 + 31t - 16t²

16 - 2 - 31t + 16t² = 0

16t² - 31t + 14 = 0

t = \dfrac{-(-31)\pm \sqrt{(-31)^2-4(16)(14)}}{2(16)}\\\\

t = 0.717 , 1.221

Hence, the time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.

Learn more about Quadratic Equations:

brainly.com/question/2263981

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