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lapo4ka [179]
3 years ago
12

Identity Structure find the rule for each function table.

Mathematics
2 answers:
nasty-shy [4]3 years ago
8 0

Answer:

y  = 4x-1

Step-by-step explanation:

We have given a table of values in which x and y are given.

We have to find the rule for function.

y  = mx+c is equation in which m is slope and c is y-intercept.

slope  = m  =  y₂-y₁ / x₂-x₁

Putting given values in above formula, we have

slope  = m =  7-3 / 2-1

m  =  4 / 1

m  =  4

y  =  4x+c           eq(1)

Now, putting x  = 3 and y = 11 in above formula, we have

11  =  4(3)+c

11  = 12+c

c  = -1

putting value of c in eq(1), we have

y  =  4x-1 is equation of function whose values are given.

Andreyy893 years ago
6 0

Answer:

The rule for given table is y = 4x - 1.

Step-by-step explanation:

From the given table it is noticed that the function passing through the points (1,3), (2,7) and (3,11).

If a line passing through the two points, then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of line is

y-3=\frac{7-3}{2-1}(x-1)

y-3=\frac{4}{1}(x-1)

y-3=4(x-1)

y-3=4x-4

Add 3 both sides.

y=4x-4+3

y=4x-1

Therefore the rule for given table is y = 4x - 1.

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If TU= 12 and UV =18, what is TV
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Answer:

its either 54 or 24 or 6 either one should work :\

Step-by-step explanation:

T might equal 6

U might equal 2

V might equal 9

OR

T might equal 4

U might equal 3

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OR

T might equal 2

U might equal 6

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4 0
4 years ago
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Step-by-step explanation:

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6 0
3 years ago
You are rolling a pair of dice what's is the probability of getting different numbers on both dice
padilas [110]

Answer:

Pr = 0.833

Step-by-step explanation:

Given

A roll of a pair of dice

Required

The probability of getting different numbers

First, list out the sample space;

We have:

S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6),(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6),

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6),(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}

The total is:

Total = 36

The outcomes of the different numbers are:

Different = \{(1, 2) (1, 3) (1, 4) (1, 5) (1, 6),(2, 1) (2, 3) (2, 4) (2, 5) (2, 6),

(3, 1) (3, 2)(3, 4) (3, 5) (3, 6),(4, 1) (4, 2) (4, 3) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) \}

The total is:

Different = 30

So, the probability of having a different outcome is:

Pr = \frac{Different}{Total}

Pr = \frac{30}{36}

Pr = 0.833

3 0
3 years ago
Someone please help me. SERIOUS answers only!!!!
IRINA_888 [86]
Hey there!

The answer should be 30%
4 0
4 years ago
Solve the equation for the indicated variable. P=5x-11 solve for x
Luden [163]
<h3><u>The variable x is equal to (p + 11)/5.</u></h3>

P = 5x - 11

<em><u>Add 11 to both sides.</u></em>

p + 11 = 5x

<em><u>Divide both sides by 5.</u></em>

(p + 11)/5 = x

3 0
4 years ago
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