Answer: The answer is C, 4 to the 21st over 5 to the 6th power.
Given rectangle RUTS, the missing reasons that justifies the five statements in the two-column proof are:
- Given
- Definition of rectangle.
- Definition of rectangle.
- By SAS Congruence Theorem.
- By CPCTC.
<h3>What is a Rectangle?</h3>
- A rectangle is a quadrilateral.
- All four angles in a rectangle are right angles.
- The opposite sides of a rectangle are parallel and congruent to each other.
Therefore, based on what we are given and the definition of a rectangle, we can establish that △URS ≅ △STU by SAS.
Since △URS ≅ △STU, therefore ∠USR = ∠SUT by CPCTC.
In conclusion, given rectangle RUTS, the missing reasons that justifies the five statements in the two-column proof are:
- Given
- Definition of rectangle.
- Definition of rectangle.
- By SAS Congruence Theorem.
- By CPCTC.
Learn more about properties of rectangle on:
brainly.com/question/2835318
a= 34 degrees
b= 28 degrees
c= 62 degrees
Step-by-step explanation:
First you know that b is 1/2 of 56 degrees or 28.
The triangle with the a in it is isoceles because the two sides are both radii.
In the triangle the top angle = 112 because it is a centeral angle to the 112 arc.
Angle a and opposite to a are equal and then have to be 34 degrees to equal 180.
We know two arc lengths are 112 and 56 and the one with angle a has to be 34x2 or 68.
a whole circle equals 360.
360-56-68-112 = 124
Angle c = 1/2 of 124, or 62 degrees
Answer:
No you do not.
This is because we can use Pythagoras Theorem to show that our location sits outside the 15 mile radius of the cell tower.
To work is out you would write the equation
Then to work out the Hypotheses you would
Which proves that the location is outside of the 15 Mile radius of the cell tower.
Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.
To find : Area (ΔMNC)
Solution: In Δ ABC, right angled at C,
AC= 6 cm, BC= 8 cm
Using pythagoras theorem
AB² =AC²+ BC²
=6²+8²
= 36 + 64
→AB² =100
→AB² =10²
→AB =10
Also, AM:MN:NB=1:2.5:1.5
Then AM, MN, NB are k, 2.5 k, 1.5 k.
→2.5 k + k+1.5 k= 10
→ 5 k =10
Dividing both sides by 2, we get
→ k =2
MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm
As Δ ACB and ΔMNC are similar by SAS.
So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.
![\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}](https://tex.z-dn.net/?f=%5Cfrac%7BAr%28ACB%29%7D%7BAr%28MNC%29%7D%3D%5B%5Cfrac%7B10%7D%7B5%7D%5D%5E%7B2%7D)
But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]
→ Area(ΔMNC)=24÷4
→Area(ΔMNC)=6 cm²
