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Mars2501 [29]
3 years ago
7

5. (05.02 MC)

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

what class is this for

please answer now

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Consider the function f(x) = 3x + 2. Evaluate f(f^1(x))
Likurg_2 [28]

Answer:

11

Step-by-step explanation:

4 0
3 years ago
Find f'(a) f(t)=2t+1/t+3
GaryK [48]
I'm going to rewrite f(t) to make it a little easier to use the power rule:
f(t)=2t+t^{-1}+3

Now just take the derivative using the power rule:
f'(t)=2-t^{-2}

Since they ask for f'(a), we need to replace the t's with a's:
f'(a)=2-a^{-2}
3 0
4 years ago
1.Write the expression in expanded form. The subscript number can be write in
enyata [817]

Answer:

(a) Expanded form:

((X_1 + X_1Y_1) - X_1Z_1) + ((X_2 + X_2Y_2) - X_2Z_2) + ((X_3 + X_3Y_3) - X_3Z_3) + ((X_4 + X_4Y_4) - X_4Z_4)

(b) The value of the expression: -21

Step-by-step explanation:

Given

\sum \limit^4_{i=1}\ ((X_i+X_iY_i) - X_iZ_i)

Solving (a): The expanded form:

This means that we substitute the values of i from 1 to 4 in the above expression.

So, the expression becomes:

((X_1 + X_1Y_1) - X_1Z_1) + ((X_2 + X_2Y_2) - X_2Z_2) + ((X_3 + X_3Y_3) - X_3Z_3) + ((X_4 + X_4Y_4) - X_4Z_4)

Solving (b): The value of the expression

To do this, we simply substitute the given values of X1, X2....... in the expression.

This gives:

So, the expression becomes:

((0 + 0*5) - 0*0) + ((1 + 1*26) - 1*-2) + ((12 + 12*-2) - 12*3) + ((-1 + -1*25) - -1*24)

Simplify each bracket

((0 + 0) - 0) + ((1 + 26) +2) + ((12 -24) - 36) + ((-1 -25) +24)

0 + 29 -48  -2

-21

<em>Hence, the result of the expression is -21</em>

5 0
3 years ago
3(x-6)-8x=-2 + 5(2x+1)
postnew [5]

Answer:

<u>x = -1</u>

Step-by-step explanation:

3(x - 6) - 8x = -2 + 5(2x + 1)

3x - 18 - 8x = -2 + 10x + 5

-5x - 18 = 10x + 3

-15x = 15

<u>x = -1</u>

3 0
3 years ago
Read 2 more answers
Please help on this ​
Anna007 [38]

Answer:

The first on is -80,

next one is -60

third one 3

last one is -54

Step-by-step explanation:

6 0
3 years ago
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